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Molarity = moles of solute/liters of solution

or, for our purposes

moles of solute = liters of solution * Molarity

moles of AgNO3 = 0,50 liters * 4.0 M

= 2.0 moles of AgNO3 needed

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Q: How many moles of agno3 are needed to prepare 0.50 l of a 4.0 m solution?
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What is the molarity of a solution if 255 grams AgNO3 is dissolved in 1500 mL of solution?

Get moles silver nitrate. 255 grams AgNO3 (1 mole AgNO3/169.91 grams) = 1.5008 moles AgCO3 --------------------------------Now; Molarity = moles of solute/Liters of solution ( 1500 ml = 1.5 Liters ) Molarity = 1.5008 moles AgNO3/1.5 Liters = 1.00 M AgNO3 ---------------------


How many mL of .117M AgNO3 solution would be required to react exactly with 3.82 moles of NaCl?

Balanced equation first! AgNO3 + NaCl -> AgCl + NaNO3 all one to one, get moles AgNO3 3.82 moles NaCl (1 mole AgNO3/1 mole NaCl) = 3.82 moles AgNO3 ------------------------------- Molarity = moles of solute/Liters of solution 0.117 M AgNO3 = 3.82 moles AgNO3/Liters Liters = 3.82/0.117 = 32.6 Liters which is 32600 milliliters which is unreasonable; check answer if you can


How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?

Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.


How many moles of NaOH are needed to prepare 2 liters of a 2.0 M solution?

4 moles or 160 g NaOH is required for one litre solution.


How many moles of NaOH needed to prepare 300 mL of a 0.2 m solution of NaOH?

You need 2,4 g NaOH (0,06 moles).

Related questions

What is the molarity of a solution if 255 grams AgNO3 is dissolved in 1500 mL of solution?

Get moles silver nitrate. 255 grams AgNO3 (1 mole AgNO3/169.91 grams) = 1.5008 moles AgCO3 --------------------------------Now; Molarity = moles of solute/Liters of solution ( 1500 ml = 1.5 Liters ) Molarity = 1.5008 moles AgNO3/1.5 Liters = 1.00 M AgNO3 ---------------------


How many mL of .117M AgNO3 solution would be required to react exactly with 3.82 moles of NaCl?

Balanced equation first! AgNO3 + NaCl -> AgCl + NaNO3 all one to one, get moles AgNO3 3.82 moles NaCl (1 mole AgNO3/1 mole NaCl) = 3.82 moles AgNO3 ------------------------------- Molarity = moles of solute/Liters of solution 0.117 M AgNO3 = 3.82 moles AgNO3/Liters Liters = 3.82/0.117 = 32.6 Liters which is 32600 milliliters which is unreasonable; check answer if you can


How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?

Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.


How many moles of hno3 are needed to prepare 5.0 of a 2.0 m solution of hno3?

10


How many moles of NaOH are needed to prepare 2 liters of a 2.0 M solution?

4 moles or 160 g NaOH is required for one litre solution.


How many moles of sodium chloride are needed to prepare 500 mL of a 0.250 M solution?

500ml = 500cm3 = 0.5dm3 0.250M = 0.250mol/dm3 number of moles = molarity x volume number of moles = 0.250mol/dm3 x 0.5dm3 = 0.125mol 0.125mol of NaCl is needed to prepare the required solution.


How many moles of NaOH needed to prepare 300 mL of a 0.2 m solution of NaOH?

You need 2,4 g NaOH (0,06 moles).


How many moles of AgNO3 does 85 grams of AgNO3 represents?

85 grams of AgNO3 represents 0,.5 moles.


What is the total number of moles of H2SO4 needed to prepare 5.0 liters of a 2.0 M solution of H2SO4?

The answer is 0,526 mL.


How many moles of Fe3O4 are needed to prepare 4.74 moles of Fe2O3?

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How many moles are in 680g of AgNO3?

Roughly 4 moles.


How many moles of KCl are needed to prepare 1.00 L of a 1.0M KCl solution?

M= moles in solution/liters so plug in what you know 3.0M of KCl solution = moles in solution/ 2.0L multiply both sides by 2.0L moles solute = 1.5 moles KCl so you need 1.5 moles KCl to prepare the solution