600ml.
A 1.3 specific gravity sulfuric acid solution means that it is 1.3 times denser than water. This solution would contain approximately 49.1% sulfuric acid by weight. It is a relatively concentrated solution and should be handled with care due to its corrosive nature.
To obtain a 12% alcohol solution, you would need to mix 12ml of alcohol with 48ml of water. This would give you a total volume of 60ml, with 12% of it being alcohol.
H2SO4 (30%-40%) added slowly to steel wool. The pH of the solution should be acidic at any given time, otherwise the ferrous ions will oxidize to the ferric state. The sulfuric acid will begin to dissolve the steel, producing hydrogen gaz.
Well if you have 99% solution of H2SO4, that means of one L you have 990 mL the acid. The density of sulphuric acid is 1.84g/mL... so that means you will have by mass 1821.6g of acid. The molecular weigth of H2SO4 is 98.1g/mol... so if you divide mass by molar mass you should get moles... which is about... 18.57moles. So that means 99% sulphuric acid is approx. 19M.
To make 1N sulfuric acid, dilute concentrated sulfuric acid (around 18M) with water in a 1:18 ratio. For example, mix 1mL of concentrated sulfuric acid with 18mL of water to obtain approximately 1N sulfuric acid solution. Always add acid to water slowly while stirring to avoid splattering and heat generation. Safety precautions should be followed when working with concentrated acids.
10 liters.
2 gallons.
Dissolve 15 g salt in 100 mL water.
How much 50 percent antifreeze solution and 40 percent antifreeze solution should be combined to give 50 gallons of 46 percent antifreeze solution?
2%
A 1.3 specific gravity sulfuric acid solution means that it is 1.3 times denser than water. This solution would contain approximately 49.1% sulfuric acid by weight. It is a relatively concentrated solution and should be handled with care due to its corrosive nature.
To obtain a solution that is twenty percent antifreeze, you would add 4 parts water to 1 part antifreeze. This means that for every 1 part of antifreeze, you would add 4 parts of water. This would result in a total of 5 parts of solution, with 1 part being antifreeze and 4 parts being water, achieving a solution that is twenty percent antifreeze.
0.25 gallons of water (or 1 quart)
To obtain a 12% alcohol solution, you would need to mix 12ml of alcohol with 48ml of water. This would give you a total volume of 60ml, with 12% of it being alcohol.
H2SO4 (30%-40%) added slowly to steel wool. The pH of the solution should be acidic at any given time, otherwise the ferrous ions will oxidize to the ferric state. The sulfuric acid will begin to dissolve the steel, producing hydrogen gaz.
Let x = the amount of 20% solution Let x + 10 = the amount of the final solution. So we have: (.20)x + (.50)(10) = (.40)(x + 10) .20x + 5 = .40x + 4 .20x = 1 x = 5 liters of 20% solution of saline.
Well if you have 99% solution of H2SO4, that means of one L you have 990 mL the acid. The density of sulphuric acid is 1.84g/mL... so that means you will have by mass 1821.6g of acid. The molecular weigth of H2SO4 is 98.1g/mol... so if you divide mass by molar mass you should get moles... which is about... 18.57moles. So that means 99% sulphuric acid is approx. 19M.