88 ml
600ml.
0.5 to 1 percent starch solution should be used
The concentration of the diluted solution will be 15(300/1000) = 4.5 %, if the percent is expressed on a weight/volume basis.
70%
Add 0,8 L of water.
2/3 of 70% and 1/3 of 10%
600ml.
10 liters.
80% water
684 ml
Let x = ounces of 50% solution, and y = ounces of 1% solution. So that we have: 0.5x + 0.01y = 8(0.2) which is a linear equation in two variables, meaning there are infinitely many choices of mixing those solutions.
2 gallons.
Dissolve 15 g salt in 100 mL water.
How much 50 percent antifreeze solution and 40 percent antifreeze solution should be combined to give 50 gallons of 46 percent antifreeze solution?
2%
0.25 gallons of water (or 1 quart)
Let x = the amount of 20% solution Let x + 10 = the amount of the final solution. So we have: (.20)x + (.50)(10) = (.40)(x + 10) .20x + 5 = .40x + 4 .20x = 1 x = 5 liters of 20% solution of saline.