To calculate the amount of pure acid in the solution, you can use the formula: amount of pure acid = volume of solution * concentration of acid. In this case, it would be 860 mL * 0.19 = 163.4 mL of pure acid in the solution.
There are 52.8 milliliters of pure acid in 440 milliliters of a 12% acid solution.
There are 90 liters of pure acid in the mixture because 120 x 0.75 = 90.
Carbonic acid is not considered a pure substance because it is a weak acid that can dissociate into carbon dioxide and water. As such, it is a solution rather than a pure substance.
Assuming that you mean that your pure acid is twice as concentrated as your 50% acid. Pretending your pure acid is at 1 mol/gallon and the 50% acid is 0.5 mol/gallon1 molgallon-1 * x gallons = x mol0.5 molgallon-1 * 4 gallons = 2 mol(x + 2) mol for (x+4) gallons = 0.8(x+2) mol / (x+4) gallons= 0.8 molgallon-1x + 2 = 0.8x + 3.20.2x = 1.2x = 6add 6 gallons of pure acid to the 4 gallons to make 10 gallons of 80% acid solution
The pH value of any acidic solution depends on the strength of the acid in the particular solution. In this instance, a dilute sulfuric acid solution shows a higher value of pH whereas the concentrated acid shows a very low value.
There are 52.8 milliliters of pure acid in 440 milliliters of a 12% acid solution.
18% of 330 = 59.4 So there are 59.3ml of pure acid in 330ml of 18% acid solution.
x=45
To find the amount of pure acid to add, set up an equation based on the amount of acid in the original solution and the final solution. Let x be the amount of pure acid to add. The amount of acid in the original solution is 0.4 × 12 = 4.8 ounces. The amount of acid in the final solution is 0.6 × (12 + x) = 4.8 + 0.6x ounces. Therefore, to get a 60% acid solution, you would need to add 10.67 ounces of pure acid.
pH less than 7
There are 90 liters of pure acid in the mixture because 120 x 0.75 = 90.
50% acid in a 6 gallon solution means that 3 gallons are acid. 9 gallons more acid will give you a total of 12 gallons of acid in a 15 gallon solution. 12 is 80% of 15.
Carbonic acid is not considered a pure substance because it is a weak acid that can dissociate into carbon dioxide and water. As such, it is a solution rather than a pure substance.
All of the moles of pure acid will have dissolved in the flask.
6 litres of 30% solution would contain 6*30/100 = 1.8 litres of pure acid.1.8 litres of pure acid, in a 12% solution means the total volume is 1.8*(100/12) = 15 litres in total. So you need to add 9 litres of pure water.6 litres of 30% solution would contain 6*30/100 = 1.8 litres of pure acid.1.8 litres of pure acid, in a 12% solution means the total volume is 1.8*(100/12) = 15 litres in total. So you need to add 9 litres of pure water.6 litres of 30% solution would contain 6*30/100 = 1.8 litres of pure acid.1.8 litres of pure acid, in a 12% solution means the total volume is 1.8*(100/12) = 15 litres in total. So you need to add 9 litres of pure water.6 litres of 30% solution would contain 6*30/100 = 1.8 litres of pure acid.1.8 litres of pure acid, in a 12% solution means the total volume is 1.8*(100/12) = 15 litres in total. So you need to add 9 litres of pure water.
Assuming that you mean that your pure acid is twice as concentrated as your 50% acid. Pretending your pure acid is at 1 mol/gallon and the 50% acid is 0.5 mol/gallon1 molgallon-1 * x gallons = x mol0.5 molgallon-1 * 4 gallons = 2 mol(x + 2) mol for (x+4) gallons = 0.8(x+2) mol / (x+4) gallons= 0.8 molgallon-1x + 2 = 0.8x + 3.20.2x = 1.2x = 6add 6 gallons of pure acid to the 4 gallons to make 10 gallons of 80% acid solution
You need 17 gallons for a 15% volume/volume mixture.