Perhaps a rephrasing of the question would help; I've never seen a hydrogen electrode so I don't know how it compares to zinc. The process being done would probably also help (are you electroplating or separating oxygen from hydrogen or ...?), as would the solution the electrodes are immersed in (does the solution react with zinc at room temperature, is it being used in a gas, ...?)
In potentiometric titration, the change in the concentration of H+ ions are monitored based on the emf measurement with respect to Saturated calomel electrode ( a reference electrode having a standard reduction potential of 0.2422 V). H+ ions concentration in terms of pH change is measured using primarily by quinhydrone electrode. Based on hydrogen electrode also it can be measured. An electrochemical cell consists of H+ ions (acid to be titrated) in contact with hydrogen gas (1 atm) or quinhydrone/ quinone should be formed and the emf (potential difference) of the cell is measured with reference to saturated calomel electrode (SCE). Then based on Nernst equation value of standard electrode potential of hydrogen ion is, EH = Eo + 0.0591 log [H+] or EH = - 0.0591 pH since Eo = 0 V and -log [H+] = pH So EMF of the cell is Ecell = ESCE - EH Ecell = 0.2422 - EH The Ecell value is plotted ( Y axis) against volume of base added (X axis). The volume corresponds to drastic Ecell change gives equivalence point of the titration. At equivalence point all the free H+ ions are replaced as H2O and this is reflected and can be inferred in the Ecell values.
Water is one of the only clear solution made of hydrogen and oxygen
There are three indicators that may be used for the titration of Fe2+ with K2Cr2O7. These are diphenylamine, diphenylbenzidine and diphenylamine sulfonate. The colour change for all three indicators is green to violet and the standard electrode potentials are all ca 0.78 V. According to Kolthoff and Sandell, this should lie between the electrode potentials of the two reduction reactions. This not being the case, phosphoric acid is added to reduce the electrode potential for the Fe3+ → Fe2+ reaction by stabilising the ferric ion.
I think Hydrogen Peroxide is a reactant,because hydrogen and oxygen are reactants so hydrogen peroxide should be a reactant.
it should be
There is no absolute measure of flexibility.
according to me anode should be oxidizing electrode as oxidation reaction takes place on anode
Water is one of the only clear solution made of hydrogen and oxygen
earth electrode should be at least 1.5 meter away from building surface...
So that scientists all over the world can easily compare their results
In potentiometric titration, the change in the concentration of H+ ions are monitored based on the emf measurement with respect to Saturated calomel electrode ( a reference electrode having a standard reduction potential of 0.2422 V). H+ ions concentration in terms of pH change is measured using primarily by quinhydrone electrode. Based on hydrogen electrode also it can be measured. An electrochemical cell consists of H+ ions (acid to be titrated) in contact with hydrogen gas (1 atm) or quinhydrone/ quinone should be formed and the emf (potential difference) of the cell is measured with reference to saturated calomel electrode (SCE). Then based on Nernst equation value of standard electrode potential of hydrogen ion is, EH = Eo + 0.0591 log [H+] or EH = - 0.0591 pH since Eo = 0 V and -log [H+] = pH So EMF of the cell is Ecell = ESCE - EH Ecell = 0.2422 - EH The Ecell value is plotted ( Y axis) against volume of base added (X axis). The volume corresponds to drastic Ecell change gives equivalence point of the titration. At equivalence point all the free H+ ions are replaced as H2O and this is reflected and can be inferred in the Ecell values.
A rule of thumb is - the arc length should be the same as the diameter of the electrode. 3/32" electrode = 3/32" arc length. 1/8" electrode = 1/8" arc length etc. The thicker the electrode coating the shorter the distance from the end of the electrode to the work. Drag rods are contact rods. E-7024 is one.
Water molecules (not particles) can be "split" into hydrogen gas (H2) and oxygen gas (O2) using electricity. The process is called electrolysis. If a DC current is applied which has sufficient voltage (about 1.5 V), oxygen will bubble off of the positive electrode, and hydrogen will bubble off of the negative electrode. Some kind of electrolyte, such as salt, should be added to the water to make it more conductive, since pure water is a very poor conductor of electricity.
Control
you should add flygon,wailord,ninjask,gardivor,electrode
Why should you compare activities for applicability
Cathode, or negative terminal of power supply