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Vmax is the maximum possible rate that can be achieved by the addition of substrate. It levels off at v max because availability of substrate is no longer a limiting factor. Km is defined by 1/2 of Vmax. In reality Vmax levels off but then the curve goes down once substrate concentration increases viscosity.

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Q: How the Vmax achieved in Michael's- Menten equation?
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How do you determine Vmax in enzyme kinetics?

Vmax is the maxim initial velocity (Vo) that an enzyme can achieve. Initial velocity is defined as the catalytic rate when substrate concentration is high, enough to saturate the enzyme, and the product concentration is low enough to neglect the rate of the reverse reaction. Therefore, the Vmax is the maximum catalytic rate that can be achieved by a particular enzyme. Km is determined as the substrate concentration at which 1/2 Vmax is achieved. This kinetic parameter therefore importantly defines the affinity of the substrate for the enzyme. These two parameters for a specific enzyme defines: Vmax - the rate at which a substrate will be converted to product once bound to the enzyme. Km - how effectively the enzyme would bind he substrate, hence affinity.


What are k-series and v-series enzymes?

A K-Series enzyme is an enzyme that changes the Km of an enzyme on the michaelis menten or lineweaver burk graphs A V-series enzyme affects the Vmax


How do you estimate the value of Vmax for two different concentrations of the substrate?

The Vmax would be the highest rate, when the enzyme is fully saturated. So as you increase substrate the Vmax will increase to a certain point (Vmax). Beyond that point, no matter how much substrate you add the Vmax will not increase.


What does increased Vmax suggest?

An increase in Vmax suggest an increase in the amount of enzyme in the reaction. Also this increase in Vmax deceases the Km vaule, which means less substrate is needed.


Suppose that the enzyme concentration was increased by a factor of four what would be the value of km and vmax?

KM would not change, since it is a constant. Vmax would half, because Vmax depends on the concentration of the enzyme.

Related questions

What is michelis menten curve how it is useful in the study of enzyme kinetics?

The michaelis menten cruve is a plot of initial velocity vs substrate concentration. From this plot one can measure a Vmax and Km.


How can calculate the michelis menten constant?

Km= 1/2 (Vmax). Remember Km is a substrate concentration not a rate.


How do you calculate Michaelis Menten constant?

The Michaelis-Menten constant (Km) is calculated by determining the substrate concentration at half of the maximum reaction rate (Vmax). This value can be obtained by plotting reaction rates against substrate concentrations and identifying the point where the reaction rate is half of Vmax. Km represents the affinity of the enzyme for its substrate.


How do you determine Vmax in enzyme kinetics?

Vmax is the maxim initial velocity (Vo) that an enzyme can achieve. Initial velocity is defined as the catalytic rate when substrate concentration is high, enough to saturate the enzyme, and the product concentration is low enough to neglect the rate of the reverse reaction. Therefore, the Vmax is the maximum catalytic rate that can be achieved by a particular enzyme. Km is determined as the substrate concentration at which 1/2 Vmax is achieved. This kinetic parameter therefore importantly defines the affinity of the substrate for the enzyme. These two parameters for a specific enzyme defines: Vmax - the rate at which a substrate will be converted to product once bound to the enzyme. Km - how effectively the enzyme would bind he substrate, hence affinity.


What physics equation do you use to find the positive position of half of the Vmax in a SHM oscillation?

Mass/Synthesised pressure = SHM Vmax


What are k-series and v-series enzymes?

A K-Series enzyme is an enzyme that changes the Km of an enzyme on the michaelis menten or lineweaver burk graphs A V-series enzyme affects the Vmax


In all of the enzymatic activity assays in which you were attempting to determine the amount?

In all of the enzymatic activity assays in which we were attempting to determine the amountof enzyme present, the experiments were carried out under very specific substrate concentrationconditions. What were those conditions, and using the Michaelis-Menten equation.explain why those conditions were chosen.In order to determine the amount of enzyme (or concentration), we chose [S]>>Km . Underthese conditions the Michealis-Menten equation reduces to:Vo = Vmax = kcat [Etotal ]


The initial rate of an enzyme catalysed reaction depend on?

Based on Michaelis-Menten enzyme kinetics, the initial rate of reaction, vi, is dependent on maximum rate Vmax, substrate concentration [S], and the enzyme's Michaelis constant Km, which represents the the tendency of the substrate/enzyme complex to dissociate. The dependence on enzyme concentration is factored into the maximum rate. The equation to describe this is: vi = Vmax([S]/(Km+[S])) Follow the link below for details.


How is the lineweaver-burk graph plotted?

The lineweaver burk plot is: y= 1/v x=1/[S] m=Km/Vmax B=1/Vmax This plot is a linear plot and follows the y=mx+b equation


What is turn over number?

In enzymology, the turnover number (also termed kcat) is defined as the maximum number of molecules of substrate that an enzyme can convert to product per catalytic site per unit of time and can be calculated as follows: kcat = Vmax/[E]T (see Michaelis-Menten kinetics).


How do you estimate the value of Vmax for two different concentrations of the substrate?

The Vmax would be the highest rate, when the enzyme is fully saturated. So as you increase substrate the Vmax will increase to a certain point (Vmax). Beyond that point, no matter how much substrate you add the Vmax will not increase.


What does increased Vmax suggest?

An increase in Vmax suggest an increase in the amount of enzyme in the reaction. Also this increase in Vmax deceases the Km vaule, which means less substrate is needed.