2HCl + Na(2)S-----> H(2)S + 2NaCl
To balance the equation Cl₂ + 2NaI -> 2NaCl + I₂ you need to ensure that the number of each element is the same on both sides of the equation. In this case, you balance the equation by adding a coefficient of 2 in front of NaCl and I₂ to balance the number of atoms of Na, Cl, and I.
The balanced equation is AgNO3 + NaCl --> AgCl + NaNO3. No coefficients are needed because everything bonds in a 1:1 molar ratio.
HCl + NaOH = H2O + NaCl is already balanced.
Your question leads me to believe that you have the following equation: Na + Cl ---> NaCl2 In that case, note there is one Na (sodium) on the left and one on the right, so they are good. There's one chloride on the left but two on the right, so placing a "2" in FRONT of the Cl on the left will balance the equation and look as such: Na + 2Cl ---> NaCl2
2NH4Cl + Na2CO3 --> 2NH3 + CO2 + H2O + 2NaCl
To balance the equation Cl₂ + 2NaI -> 2NaCl + I₂ you need to ensure that the number of each element is the same on both sides of the equation. In this case, you balance the equation by adding a coefficient of 2 in front of NaCl and I₂ to balance the number of atoms of Na, Cl, and I.
The formula unit of sodium chloride is NaCl.
To determine the coefficient that should be placed in front of NaCl to balance a chemical equation, you need to analyze the reactants and products involved in the reaction. Balance the number of atoms of each element on both sides of the equation, ensuring that they are equal. If you provide the complete unbalanced equation, I can help you find the specific coefficient needed for NaCl.
NaNO3(ac) + KCl(ac)-----> NaCl(ac) + KNO3(ac)
The balanced equation is AgNO3 + NaCl --> AgCl + NaNO3. No coefficients are needed because everything bonds in a 1:1 molar ratio.
NaHCO3 + HCl = CO2 + H2O + NaCl
This equation does not balance because 2 chlorine salts do not react with eachother. However, they are both highly soluable in water. By adding H2O, this equation can be balanced.
HCl + NaOH = H2O + NaCl is already balanced.
The equation is: NaCl----------Na++ Cl-
Your question leads me to believe that you have the following equation: Na + Cl ---> NaCl2 In that case, note there is one Na (sodium) on the left and one on the right, so they are good. There's one chloride on the left but two on the right, so placing a "2" in FRONT of the Cl on the left will balance the equation and look as such: Na + 2Cl ---> NaCl2
The overall equation is: CaCO3(s) + 2NaCl (aq) Na2CO3(aq) + CaCl2(aq),
NaCl doesn't burn.