6NH4ClO4 + 10Al = 5Al2O3 + 3N2 + 6HCl + 9H2O
To balance the equation Cl2 + H2O = HCl + HClO3, you need to add coefficients to the molecules so there is an equal number of atoms on each side of the equation. The balanced equation is: 3Cl2 + 6H2O = 6HCl + 2HClO3.
To balance the equation SiCl4 -> Si + Cl2, you need to have the same number of each type of atom on both sides of the equation. Start by balancing the silicon atoms first, then the chlorine atoms. In this case, the balanced equation is SiCl4 -> Si + 2Cl2.
HCl + NaOH = H2O + NaCl is already balanced.
The balanced equation is as follows: 2HI + Cl2 --> 2HCl + I2
The balanced equation for the reaction between KI and Cl2 to form KCl and I2 is: 2KI + Cl2 -> 2KCl + I2 This equation is already balanced.
The balanced equation for the reaction between sodium (Na) and chlorine (Cl2) to form sodium chloride (NaCl) is 2Na + Cl2 -> 2NaCl. This equation is balanced because it has an equal number of each type of atom on both sides of the reaction arrow.
2ki and 2kci
To balance the equation Cu + Cl2 → CuCl2, you need to make sure there are the same number of atoms on each side: 2 Cu atoms on the left, 2 Cl atoms in CuCl2, and 2 Cl atoms in Cl2. So, the balanced equation is Cu + Cl2 → CuCl2.
To balance the equation Cl2 + H2O = HCl + HClO3, you need to add coefficients to the molecules so there is an equal number of atoms on each side of the equation. The balanced equation is: 3Cl2 + 6H2O = 6HCl + 2HClO3.
This chemical reaction is:CS2 + 3 Cl2 = CCl4 + S2Cl2
To balance the equation SiCl4 -> Si + Cl2, you need to have the same number of each type of atom on both sides of the equation. Start by balancing the silicon atoms first, then the chlorine atoms. In this case, the balanced equation is SiCl4 -> Si + 2Cl2.
HCl + NaOH = H2O + NaCl is already balanced.
To balance the redox reaction involving H2O, Cl2, P4, POCl3, and HCl, you need to first assign oxidation numbers to each element and then balance the atoms and charges. The balanced equation is: 4 H2O + 6 Cl2 + P4 -> 4 H3PO4 + 6 POCl3 + 4 HCl.
The balanced equation is as follows: 2HI + Cl2 --> 2HCl + I2
Ca + Cl2 ----> CaCl Step 1) Ca + Cl2 ----> 2 CaCl There are 2 Cl's on the reaction side so you need 2 on the Product side Step 2) 2Ca + Cl2 ----> 2 CaCl There are now 2 Ca on the product side and you need 2 on the reactant side Voila!
the equation Fe + Cl2 = FeCl3 would be balanced as...2Fe + 3Cl2 = 2FeCl3
The balanced equation for the reaction between KI and Cl2 to form KCl and I2 is: 2KI + Cl2 -> 2KCl + I2 This equation is already balanced.