the reaction would shift to favor the side with the most moles of gas. (apex).
The answer is "The equilibrium would shift to reduce the pressure change" on Apex
The answer is "The equilibrium would shift to reduce the pressure change" on Apex
The equalibrium would shift to reduce the pressure
Remains the same
A stress could be adding/taking away reactant/product. Or a change in temp and pressure (for gases). It depends on the system. Some of them get ulcers, but others just start drinking heavily. A system at equilbrium responds to a stress by shifting left or right (toward the reactants or toward the products) so as to minimize the effect of the disturbance. This is called LeChatelier's Principle. Some stresses can be a temperature change, a change in the concentration of one of the reactants or products, and a pressure change (if the reaction involves any reactants or products in the gaseous phase).
The answer is "The equilibrium would shift to reduce the pressure change" on Apex
The answer is "The equilibrium would shift to reduce the pressure change" on Apex
The answer is "The equilibrium would shift to reduce the pressure change" on Apex
The equalibrium would shift to reduce the pressure
the reaction would shift to favor the side with the most moles of gas. (apex).
the reaction would shift to favor the side with the most moles of gas. (apex).
the reaction would shift to favor the side with the most moles of gas. (apex).
Increasing the pressure of a gas the volume decrease.
Heat of reaction.
Yes. If the pressure is increased, even with a noble gas, the reaction equilibrium will shift to alleviate and lower that increased pressure (if there are more moles of gas on one side of the reaction than the other).
the reaction would shift to favor the side with the most moles of gas
The total number of gas molecules will decrease.