Boron has the configuration with two filled shells and one outer electron. The outer electron has L=1, S=1/2, so J = 3/2 or 1/2. Hund's rules imply the term is the ground state term as in hydrogen.
BCl3 is the formula for Boron Chloride. As a matter of interest it does not obey the octet rule. It is also called a Lewis Acid.
No, BCl3 does not follow the octet rule as boron only has 6 valence electrons in this molecule. Boron can form stable compounds with less than an octet due to its electron deficiency.
Boron is an exception to the octet rule because it only has six electrons in its outer shell, so it can form stable compounds with fewer than eight electrons. This occurs because boron is in the second row of the periodic table and can form stable compounds by sharing fewer electrons.
First, it helps to draw out the Lewis structure. Boron, being the least electronegative element is in the center, with the three Bromines singly bonded around it. Each Br has an octet of electrons (3 lone pairs plus the single bond) and there are no electrons left over to go onto the Boron. This leaves Boron without an octet, but Boron is an exception to the octet rule so that's okay. So, no BBr3 does not follow the octet rule.
Yes, it should be capitalized. Capitalization of elements and compounds are a general rule.
Three rules aufbau principle, the pauli exclusion,and the hunds rule
In general, boron will form 3 covalent bonds, using each of its 3 valence shell electrons (sharing them). This will of course violate the octet rule, but obeys the sextet rule, and this is what makes boron stable. It (along with aluminum, eg.) do not obey the octet rule.
Boron atoms do not follow the octet rule. This is because boron typically forms compounds with fewer than 8 electrons around it due to its atomic structure. Boron forms stable compounds by sharing electrons in covalent bonds and can have as few as 6 electrons in its valence shell.
BCl3 is the formula for Boron Chloride. As a matter of interest it does not obey the octet rule. It is also called a Lewis Acid.
No, BCl3 does not follow the octet rule as boron only has 6 valence electrons in this molecule. Boron can form stable compounds with less than an octet due to its electron deficiency.
Boron is an exception to the octet rule because it only has six electrons in its outer shell, so it can form stable compounds with fewer than eight electrons. This occurs because boron is in the second row of the periodic table and can form stable compounds by sharing fewer electrons.
First, it helps to draw out the Lewis structure. Boron, being the least electronegative element is in the center, with the three Bromines singly bonded around it. Each Br has an octet of electrons (3 lone pairs plus the single bond) and there are no electrons left over to go onto the Boron. This leaves Boron without an octet, but Boron is an exception to the octet rule so that's okay. So, no BBr3 does not follow the octet rule.
Hund's Rule states that within a sublevel, electrons will fill empty orbitals before pairing up. This is to maximize the spin of the electrons and stabilize the atom. It helps to explain the arrangement of electrons in an atom's electron cloud.
Yes, it should be capitalized. Capitalization of elements and compounds are a general rule.
Boron does not need an octet in its valence shell because it is an exception to the octet rule due to its electron configuration and bonding behavior. Boron typically forms stable compounds with fewer than eight electrons in its outer shell.
Boron trichloride does not follow the octet rule. Boron does not allow the eight required electrons in the outer shell.
There are exactly three electron pairs attached to the Boron atom, each one of them bonded to a chlorine atom as well.