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If 0.55 g of a gas dissolves in 1.0 L of water at 20.0 KPa of pressure how much will dissolve at 110.0 KPa of pressure?
Kinchuy
Known: s1= .55g/'
P1= 20.0 Kpa
P2= 110 Kpa
Unknown s2
Rearrange henrys law to get
S2= s1(p2/p1)
S2=.55 g/l (100kpa/20kpa)
Solve for s2
Wiki User
∙ 12y ago
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