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If a nugget of iron pyrite and a nugget of gold each have a mass of 50 g what can you conclude about the volume of each nugget?
Agreed with your correspodent 'Answer Bot'. However, do not be 'fooled' by iron pyrites'. It is known as 'Fool's Gold' , because its coloiur is very similar to Gold. However, Gold has a rounded form , whereas Iron Pyrites has a more angular form .
A nugget of gold is placed in a graduated cylinder that contains 85 mL of water The water level rises to 225 mL after the nugget is added to the cylinder What is the volume of the gold nugget?
The volume of the gold nugget can be calculated by finding the difference in volume before and after adding the nugget. The volume of the gold nugget is 225 mL (final volume) - 85 mL (initial volume) = 140 mL.
A nugget of gold is placed in a graduated cylinder that contains 80 ml of water the water level rises to 225 ml after the nugget is added to the cylinder what is the volume of the gold nugget?
The volume of the gold nugget can be calculated by subtracting the final volume (225 ml) from the initial volume (80 ml) of water in the graduated cylinder. Therefore, the volume of the gold nugget is 145 ml.
A graduated cylinder contains 250ml of water.after adding a nugget of gold to the waterthe cylinder holds 265ml of liquid. What is the volume of the nugget.?
The volume of the nugget of gold is 15 ml because the increase in volume from 250 ml to 265 ml is the volume displaced by the nugget of gold.
What is the mass of a piece of pyrite that has a volume of 10 ml?
The density of pyrite is about 5 g/cm³. To find the mass of the pyrite, you can use the formula: mass = density x volume. Therefore, in this case, the mass of the pyrite would be 50 grams.
The density of gold is 19.3 g cm3 The density of iron pyrite is 5.0 g cm3 If a nugget of iron pyrite and a nugget of gold each have a mass of 50 g what can you conclude about the volume of each nugget?
The nugget of gold has a volume of 2.6 cm3, and the nugget of pyrite has a volume of 10 cm3.
The density of gold is 19.3 gcm The density of iron pyrite is 5.0 gcm a nugget of iron pyrite and a nugget of gold each have a mass of 50 g what can you conclude about the volume of each nugget?
To find the volume of each nugget, we can use the formula ( \text{Volume} = \frac{\text{Mass}}{\text{Density}} ). For gold, the volume would be ( \frac{50 , \text{g}}{19.3 , \text{g/cm}^3} \approx 2.59 , \text{cm}^3 ), while for iron pyrite, the volume would be ( \frac{50 , \text{g}}{5.0 , \text{g/cm}^3} = 10 , \text{cm}^3 ). Therefore, the volume of the nugget of iron pyrite is significantly larger than that of the gold nugget.
If a nugget of iron pyrite and a nugget of gold each have a mass of 50 g what can you conclude about the volume of each nugget?
Agreed with your correspodent 'Answer Bot'. However, do not be 'fooled' by iron pyrites'. It is known as 'Fool's Gold' , because its coloiur is very similar to Gold. However, Gold has a rounded form , whereas Iron Pyrites has a more angular form .
A nugget of gold is placed in a graduated cylinder that contains 85 mL of water The water level rises to 225 mL after the nugget is added to the cylinder What is the volume of the gold nugget?
The volume of the gold nugget can be calculated by finding the difference in volume before and after adding the nugget. The volume of the gold nugget is 225 mL (final volume) - 85 mL (initial volume) = 140 mL.
A nugget of gold is placed in a graduated cylinder that contains 80 ml of water the water level rises to 225 ml after the nugget is added to the cylinder what is the volume of the gold nugget?
The volume of the gold nugget can be calculated by subtracting the final volume (225 ml) from the initial volume (80 ml) of water in the graduated cylinder. Therefore, the volume of the gold nugget is 145 ml.
How can you express the volume of a gold nugget using cubic units?
Submerge it in water and determine the volume (in cubic centimeters) that it displaces. That will be the volume of the nugget.
A graduated cylinder contains 250ml of water.after adding a nugget of gold to the waterthe cylinder holds 265ml of liquid. What is the volume of the nugget.?
The volume of the nugget of gold is 15 ml because the increase in volume from 250 ml to 265 ml is the volume displaced by the nugget of gold.
What is the mass of a piece of pyrite that has a volume of 10 ml?
The density of pyrite is about 5 g/cm³. To find the mass of the pyrite, you can use the formula: mass = density x volume. Therefore, in this case, the mass of the pyrite would be 50 grams.
Is a Nugget real gold or fools gold if a it has a mass of 100.0 g and displaces the water level in a graduated cylinder by 15.0cm3 from 10.0cm3?
density=g/cm3 The density of Gold is 19.3g/cm3 The density of Fool's Gold (pyrite) is 5g/cm3 The question is slightly ambiguous as first written so two calculations are given: # 100/15= 6.666g/cm3 So this nugget is possibly pyrite and not gold. 100/5= 20g/cm3 So this nugget is possibly gold.
If you have 80mL of water and you add a gold nugget in the water rises 225mL what is the volume of gold nugget?
145
What is the mass of a piece of pyrite that has a volume of 40cm3?
Iron pyrite (FeS2) has a density of 4.8 to 5.0 grams per cm3. A piece of volume 40 cm3 would, therefore have a mass of volume*density = 192 to 200 grams.
A nugget of gold is placed in a graduated cylinder that contains 80 mL of water the water level rises to 255 L after the nugget is added to the cylinder what is the volume of the gold nugget?
Agreed with your correspondent(AnswerBot)!!! However, it must be a huge measuring cylinder if it has a volume of 255 L . I think you mean 255 mL. 255 L is 255 litres = 255,000 mL , which is a quarter of a cubic metre. Please ensure that you correctly insert the units.
