Vb
λ - wavelength (NM) c - speed of light (3x108 m/s)= 162 000 nmf - Frequency (Hz)λ = c \ f600=162 000 nm\ f f=270 Hz
The longest wavelength that can dissociate a molecule of HI is determined by the ionization energy of the molecule. For HI, which has an ionization energy of 10.09 eV, the corresponding longest wavelength would be about 123 nm.
The significance of the wavelength 680 nm in photosynthesis is that it corresponds to the peak absorption of light by chlorophyll a, the primary pigment responsible for capturing light energy during the light-dependent reactions of photosynthesis. This specific wavelength is optimal for driving the process of photosynthesis and converting light energy into chemical energy.
The energy of the electron decreased as it moved to a lower energy state, emitting a photon with a wavelength of 550 nm. This decrease in energy corresponds to the difference in energy levels between the initial and final states of the electron transition. The energy of the photon is inversely proportional to its wavelength, so a longer wavelength photon corresponds to lower energy.
The wavelength of the hydrogen atom in the 2nd line of the Balmer series is approximately 486 nm. This corresponds to the transition of an electron from the third energy level to the second energy level in the hydrogen atom.
The energy is 18,263.10e4 joules.
λ - wavelength (NM) c - speed of light (3x108 m/s)= 162 000 nmf - Frequency (Hz)λ = c \ f600=162 000 nm\ f f=270 Hz
Photons are in action units joule-seconds.
The energy of a photon can be calculated using the equation E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon. Plugging in the values for h, c, and λ, we can calculate the energy of one photon at 400 nm. To find the energy of 1 mol of photons, we would multiply the energy of one photon by Avogadro's number.
Since the energy of a photon is inversely proportional to its wavelength, for a photon with double the energy of a 580 nm photon, its wavelength would be half that of the 580 nm photon. Therefore, the wavelength of the photon with twice the energy would be 290 nm.
To calculate the energy of photons, you can use the equation E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength. First, convert the wavelength to meters (655 nm = 655 x 10^-9 m). Plug the values into the equation to find the energy per photon, and then multiply by Avogadro's number to get the total energy for 3.0 moles of photons.
The number of electrons emitted when calcium is flashed with light of a certain wavelength and intensity depends on the photoelectric effect, which is related to the energy of the photons hitting the metal. Without the energy of the photons and the work function of calcium, we cannot determine the number of electrons emitted.
The energy of a photon with a wavelength of 500 nm is approximately 2.48 keV.
Transition B produces light with half the wavelength of Transition A, so the wavelength is 200 nm. This is due to the inverse relationship between energy and wavelength in the electromagnetic spectrum.
The number of photons in one joule of light is inversely proportional to their wavelength. Since red light at 650 nm has a longer wavelength than blue light, which typically has a shorter wavelength (around 450 nm), there will be more photons in one joule of red light than in one joule of blue light. Therefore, the number of photons in one joule of red light is greater than the number of photons in one joule of blue light.
The longest wavelength that can dissociate a molecule of HI is determined by the ionization energy of the molecule. For HI, which has an ionization energy of 10.09 eV, the corresponding longest wavelength would be about 123 nm.
If a certain source emits radiation of a wavelength of 400 nm then the energy in a mole of photons of this radiation can be found using E = hc/w. The energy in kJ/mol of a mole of these photons is approximately 300 kJ / mole.