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I think the answer is 0.258 grams of NO2 per liter of air.

I figured that out like this:

1.29g/l x 1,000,000parts = 1,290,000ppm/g/l

1,290,000ppm/g/l x 0.2ppm = 258,000ppm/g/l

258,000ppm/g/l / 1,000,000ppm = 0.258g/l

Please anyone correct me if I'm wrong.

Good luck with whatever your trying to work out.

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Q: If air has an average density of 1.29 grams per liter and NO2 is reported at 0.20 ppm what mass of NO2 is found in 1.00 liter of air?
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