The pOH is 6,4.
The pOH is 6,4.
The pOH is 6,4.
The hydroxide ion concentration of a solution with a pH of 10.95 is 1.26 x 10^-11 mol/L. This can be calculated using the formula [OH-] = 10^(-pH).
The pOH of ammonia is approximately 4.7. Ammonia, NH3, is a weak base with a Kb value of approximately 1.8 x 10^-5. To find the pOH, you would first find the pH of the solution using the equilibrium constant for the base dissociation reaction and then use the relationship pOH = 14 - pH.
10.7(pH) - 14 = 3.3 (pOH)
The pOH is 6,4.
The pOH is 6,4.
Yes, if both solutions are at 25oC then in both solutions this is valid: pH + pOH = 14.0
pH + pOH =14
The hydroxide ion concentration of a solution with a pH of 10.95 is 1.26 x 10^-11 mol/L. This can be calculated using the formula [OH-] = 10^(-pH).
The pOH of ammonia is approximately 4.7. Ammonia, NH3, is a weak base with a Kb value of approximately 1.8 x 10^-5. To find the pOH, you would first find the pH of the solution using the equilibrium constant for the base dissociation reaction and then use the relationship pOH = 14 - pH.
10.7(pH) - 14 = 3.3 (pOH)
1.8
It will have a pOH of 12. Because pH+pOH=14
The pOH of a solution can be calculated using the relationship between pH and pOH, which is given by the equation pH + pOH = 14. If the pH of a solution is 7.0, then the pOH can be found by rearranging the equation: pOH = 14 - pH. Therefore, pOH = 14 - 7.0 = 7.0. Thus, the pOH of the solution is also 7.0.
pH is -log[H(subscript 3)O+] pOH is the [OH-] pOH = 14 - pH apex
pH + pOH =14