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Think about it, the overall charge of CaH2 is neutral (meaning a charge of 0). One of the oxidation rules states that H has a charge of -1 if it is apart of a hydride (Ex LiH, CaH2 is also a hydride). Because there are 2 Hs, it's charge would be -2. If you add the charge of calcium which is 2 with the hydrogens charge -2 you would get 0, which is right because the molecule is neutral.

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Sulfur's oxidation number is -2.

The Oxidation number of S here is to be calculated using the oxidation number of H (+1). All compounds' oxidation numbers must sum up to zero.

H2S oxidation number: 2(+1) + (x) = 0

x = -2

Sulfur's oxidation number is -2.

then oxidation number is �2

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Q: In the compound H2S hydrogen has an oxidation number of 1 plus and sulfur has an oxidation number of?
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In the compound H2 S hydrogen has an oxidation number of 1 plus and sulfur has an oxidation number of?

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