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It is different compound to compound. Sulfur generally shows +6 and +4.

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What is the oxidation number of sulfur in S4O6?

Regarding the oxidation states of the atoms in the tetrathionate ion: The tetrathionate polyatomic ion is made of four sulfur atoms, each with an oxidation number of +1, and six oxygen atoms each with an oxidation number of -1. Note, this is one of the rare exceptions to the 'rule' that oxygen normally has a minus two oxidation number. Other -1 oxygen compounds are the peroxides. An interesting half reaction is the oxidation of two thiosulfate ions to tetrathionate, in which sulfur has an oxidation number of +2 in the reactant and +1 in the product. Oxygen has an oxidation number of -2 in the reactant, and -1 in the product. 2S2O3-2 ----> S4O6-2 + 2 e-


What is the oxidation number of sulphur in CS2?

The oxidation number of sulfur in CS2 is -2. In carbon disulfide (CS2), each carbon atom has an oxidation number of +4, which means the two sulfur atoms must have oxidation numbers that add up to -8 to balance the charge of the molecule. Hence, each sulfur atom has an oxidation number of -2.


What is the oxidation number of H2 S O4?

The oxidation number of hydrogen is +1, the oxidation number of sulfur is +6, and the oxidation number of oxygen is -2. In H2SO4, there are 2 hydrogen atoms (totaling +2), 1 sulfur atom (+6), and 4 oxygen atoms (totaling -8). The sum of the oxidation numbers should equal the charge of the compound, which is 0, so the oxidation number of sulfur in H2SO4 is +6.


Which compound has sulfur as an oxidation number of -2?

Hydrogen sulfide (H2S) is a compound that contains sulfur with an oxidation number of -2. In this compound, sulfur is bonded to two hydrogen atoms, each contributing a +1 oxidation state, resulting in a total oxidation state of -2 for sulfur.


What is the oxidation number of SO2 in ions and compound?

In a whole, sulfur dioxide molecule has oxidation number 0. Sulfur has +4 oxidation number as it is bonded with two oxygen atoms through four covalent bonds. Oxygen atoms have oxygen number of -2 each.

Related Questions

What is the oxidation number of sulfur in S4O6?

Regarding the oxidation states of the atoms in the tetrathionate ion: The tetrathionate polyatomic ion is made of four sulfur atoms, each with an oxidation number of +1, and six oxygen atoms each with an oxidation number of -1. Note, this is one of the rare exceptions to the 'rule' that oxygen normally has a minus two oxidation number. Other -1 oxygen compounds are the peroxides. An interesting half reaction is the oxidation of two thiosulfate ions to tetrathionate, in which sulfur has an oxidation number of +2 in the reactant and +1 in the product. Oxygen has an oxidation number of -2 in the reactant, and -1 in the product. 2S2O3-2 ----> S4O6-2 + 2 e-


What is the oxidation number of sulphur in CS2?

The oxidation number of sulfur in CS2 is -2. In carbon disulfide (CS2), each carbon atom has an oxidation number of +4, which means the two sulfur atoms must have oxidation numbers that add up to -8 to balance the charge of the molecule. Hence, each sulfur atom has an oxidation number of -2.


What is the oxidation number of H2 S O4?

The oxidation number of hydrogen is +1, the oxidation number of sulfur is +6, and the oxidation number of oxygen is -2. In H2SO4, there are 2 hydrogen atoms (totaling +2), 1 sulfur atom (+6), and 4 oxygen atoms (totaling -8). The sum of the oxidation numbers should equal the charge of the compound, which is 0, so the oxidation number of sulfur in H2SO4 is +6.


Which compound has sulfur as an oxidation number of -2?

Hydrogen sulfide (H2S) is a compound that contains sulfur with an oxidation number of -2. In this compound, sulfur is bonded to two hydrogen atoms, each contributing a +1 oxidation state, resulting in a total oxidation state of -2 for sulfur.


What is the oxidation number of SO2 in ions and compound?

In a whole, sulfur dioxide molecule has oxidation number 0. Sulfur has +4 oxidation number as it is bonded with two oxygen atoms through four covalent bonds. Oxygen atoms have oxygen number of -2 each.


What is the oxidation number of sulfur in aluminium sulfate?

The oxidation number of sulfur in aluminum sulfate is +6. This is because each oxygen atom has an oxidation number of -2, and there are four oxygen atoms in the sulfate ion (SO4). The overall charge of the sulfate ion is -2, so the oxidation number of sulfur must be +6 to balance the charge.


What is the oxidation number for HSO4?

H2SO4 is a compound and as such does not have an oxidation number. The individual atoms in this compound have oxidation number +1 for each hydrogen atom, +6 for sulfur, and -2 for each oxygen atom.


What is the oxidation number of sulfur in the tetrathionate ion S4O62-?

In the tetrathionate ion (S4O6)2-, the total charge of the ion is 2-. Each oxygen atom has an oxidation number of -2, totaling -12 for all six oxygen atoms. Since the overall charge is 2-, the sum of the oxidation numbers of sulfur atoms must equal +2. With four sulfur atoms present, each sulfur atom in the tetrathionate ion has an oxidation number of +6.


What is the oxidation number of SF6?

The oxidation number of sulfur in SF6 is +6 because fluorine is more electronegative than sulfur and each fluorine atom has an oxidation number of -1. As there are six fluorine atoms surrounding the sulfur atom in SF6, the total charge from fluorine is -6, making the oxidation number of sulfur +6 to balance the charges.


What is the oxidation number of sulphur in sulphur powder?

The oxidation number of sulfur in sulfur powder (S8) is 0. Each sulfur atom in the elemental form has an oxidation number of 0.


What is the oxidation no Of S In s4o6-2?

To determine the oxidation number of sulfur (S) in the polyatomic ion S4O6^2-, we can set up an equation where the sum of the oxidation numbers equals the charge of the ion. In this case, the total charge is -2. Each oxygen atom has an oxidation number of -2, so the total oxidation number contributed by oxygen is -12. To solve for sulfur, we set up the equation: 4x + 6(-2) = -2, where x is the oxidation number of sulfur. By solving this equation, we find that the oxidation number of sulfur in S4O6^2- is +5.


What is the oxidation number of S in S2O8?

This is the thiosulfate ion. Sulfur shows +6 oxidation number.