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In the equation 3Na Plus AlCl30 equals 3NaCl plus Al how many aluminum molecules will be produced if you have 30 molecules of sodium?
If you have 30 molecules of sodium reacting with aluminum chloride (AlCl3), they will produce 10 molecules of aluminum. This is because the balanced equation shows that 3 moles of sodium react with 1 mole of aluminum, producing 1 mole of aluminum.
How many moles of of aluminum chloride could be produced from 29.0 g of aluminum?
To determine the moles of aluminum chloride produced, you need to use the balanced chemical equation. If aluminum reacts with chlorine to form aluminum chloride, the molar ratio is 2:3. First, determine the moles of aluminum using its molar mass, then use the molar ratio to find the moles of aluminum chloride that could be produced.
How many grams of aluminum chloride could be produced from 34.0 grams of aluminum and 39.0 grams of chlorine gas?
To find the limiting reactant, we need to calculate the moles of each reactant. Then, use the stoichiometry of the balanced chemical equation to determine which reactant limits the amount of aluminum chloride that can be produced. Finally, calculate the mass of aluminum chloride produced based on the limiting reactant.
When 4 moles of aluminum are allowed to react with an excess of chlorine gas CL2 how many moles of aluminum chlorde are produced?
When 4 moles of aluminum react with an excess of chlorine gas (Cl2), 4 moles of aluminum chloride are produced because the balanced chemical equation for this reaction is: 2 Al + 3 Cl2 -> 2 AlCl3 Since the mole ratio between aluminum and aluminum chloride is 2:2, it means that for every 2 moles of aluminum, 2 moles of aluminum chloride are produced.
When aluminum and sulfur react which compound is produced?
When aluminum and sulfur react, aluminum sulfide is produced.
In the equation 3Na Plus AlCl30 equals 3NaCl plus Al how many aluminum molecules will be produced if you have 30 molecules of sodium?
If you have 30 molecules of sodium reacting with aluminum chloride (AlCl3), they will produce 10 molecules of aluminum. This is because the balanced equation shows that 3 moles of sodium react with 1 mole of aluminum, producing 1 mole of aluminum.
How many grams of aluminum hydroxide are obtained from 15.7 of aluminum sulfide?
To find the grams of aluminum hydroxide from 15.7 grams of aluminum sulfide, you first need to balance the chemical equation. The balanced equation is 2Al2S3 + 6H2O -> 4Al(OH)3 + 3H2S. Next, calculate the molar mass of aluminum sulfide (Al2S3) and aluminum hydroxide (Al(OH)3), then use the stoichiometry from the balanced equation to find the grams of aluminum hydroxide produced.
When 0.440 mol of aluminum are allowed to react with an excess of chlorine gas Cl2 how many moles of aluminum chloride are produced?
The balanced chemical equation for the reaction between aluminum and chlorine is 2Al + 3Cl2 -> 2AlCl3. This means that for every 2 moles of aluminum that react, 2 moles of aluminum chloride are produced. Therefore, if 0.440 mol of aluminum is used, it will produce 0.440 mol of aluminum chloride.
How many moles of of aluminum chloride could be produced from 29.0 g of aluminum?
To determine the moles of aluminum chloride produced, you need to use the balanced chemical equation. If aluminum reacts with chlorine to form aluminum chloride, the molar ratio is 2:3. First, determine the moles of aluminum using its molar mass, then use the molar ratio to find the moles of aluminum chloride that could be produced.
How many grams of aluminum chloride could be produced from 34.0 grams of aluminum and 39.0 grams of chlorine gas?
To find the limiting reactant, we need to calculate the moles of each reactant. Then, use the stoichiometry of the balanced chemical equation to determine which reactant limits the amount of aluminum chloride that can be produced. Finally, calculate the mass of aluminum chloride produced based on the limiting reactant.
When 4 moles of aluminum are allowed to react with an excess of chlorine gas CL2 how many moles of aluminum chlorde are produced?
When 4 moles of aluminum react with an excess of chlorine gas (Cl2), 4 moles of aluminum chloride are produced because the balanced chemical equation for this reaction is: 2 Al + 3 Cl2 -> 2 AlCl3 Since the mole ratio between aluminum and aluminum chloride is 2:2, it means that for every 2 moles of aluminum, 2 moles of aluminum chloride are produced.
When aluminum and sulfur react which compound is produced?
When aluminum and sulfur react, aluminum sulfide is produced.
How many oxygen molecules are produced from the splitting of two molecules of water if the balanced equation for the reaction is as follows 2H2O 2H2 plus O2?
Four oxygen molecules are produced from the splitting of two molecules of water. This is because for every two molecules of water that split, one molecule of O2 is produced according to the balanced equation shown.
If you had excess aluminum how many moles of aluminum chloride could be produced from 31.0 g of chlorine gas Cl2?
To calculate the moles of aluminum chloride produced, you would first need to determine the limiting reactant. Compare the moles of each reactant (Aluminum and Cl2) using their molar masses. Whichever reactant produces fewer moles of aluminum chloride would be the limiting reactant. Once you have that, you can use the stoichiometry of the balanced chemical equation to calculate the moles of aluminum chloride produced.
What is the theoretical yield of chromium that can be produced by the reaction of 40.0 g of Cr2O3 g of aluminum?
To determine the theoretical yield of chromium produced, you first need to balance the chemical equation for the reaction between Cr2O3 and aluminum. Next, calculate the molar mass of Cr2O3 to find the moles used in the reaction. Use the stoichiometry of the balanced equation to find the moles of chromium that can be produced, and then convert that to grams.
How many grams of aluminum chloride can be made from 67.0 grams of aluminium and excess hydrochloric acid?
To determine the amount of aluminum chloride that can be produced, you need to consider the stoichiometry of the reaction between aluminum and hydrochloric acid. The balanced equation is 2Al + 6HCl → 2AlCl3 + 3H2. From the equation, 2 moles of aluminum produce 2 moles of aluminum chloride. You can use the molar mass of aluminum chloride to convert moles to grams.
When 4 moles of aluminum are allowed to react with an excess of chlorine gas Cl2 how many moles of aluminum chloride are produced?
When 4 moles of aluminum react with an excess of chlorine gas, 4 moles of aluminum chloride are produced. This is because the balanced chemical equation for the reaction is: 2Al + 3Cl2 -> 2AlCl3 This means that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride, so 4 moles of aluminum will produce 4 moles of aluminum chloride.
