Ionization energy increase from left to right.
Ionization decreases going down a cloumn.
Answer= Cs, K, Li
The noble gases such as helium, neon, argon, and xenon typically have the highest ionization energies on the periodic table. This is because they have a full valence shell of electrons which makes it difficult to remove an electron.
Lithium ====> Li , Electronic configuration { 1S2 2S1 } So we have only first ionization An the second will be from Complete stable energy level that need great amount of energy to remove it And that is impossible
Rb
The element with the smallest first ionization energy is Francium, as it is located in Group 1 of the periodic table and has the largest atomic size. Among the elements listed, lithium (Li) would have the smallest first ionization energy as it is closer to the upper right of the periodic table compared to sodium (Na), potassium (K), and rubidium (Rb).
K (lowest) Na Li B N (highest)
Atoms of alkaline metals: Rb, Cs, Fr, K, Na, Li. They have a low ionization potential. This potential is expressed in kJ/mol - molar ionization energy and is different for the first, second, third...n electron.
Yes, rubidium (Rb) is more reactive than lithium (Li), potassium (K), sodium (Na), and cesium (Cs). In the alkali metal group, reactivity increases as you move down the periodic table due to the increasing atomic size and the decreasing ionization energy, which makes it easier for the atoms to lose their outermost electron. Thus, Rb, being below K and Na, is more reactive than all of them. However, cesium (Cs) is even more reactive than rubidium.
The noble gases such as helium, neon, argon, and xenon typically have the highest ionization energies on the periodic table. This is because they have a full valence shell of electrons which makes it difficult to remove an electron.
The element that has the highest second ionization energy is Li. When you remove the first electron from Li you are down to the 1s orbital. They are harder to remove because they are closest to the nucleus.
Smallest to largest is going down the group 1. I.e. Li is smallest<Rb<Cs
It's carbon. The trend for 1st ionization energy is that it increases as you move left-to-right across a period. As you move in that direction across period 2, ionization energy increases, and since carbon is the most to the right, it has the highest 1st I.E.
It is difficult to remove electron from He than Li. LI easily loses electron and reach stable state.
Lithium ====> Li , Electronic configuration { 1S2 2S1 } So we have only first ionization An the second will be from Complete stable energy level that need great amount of energy to remove it And that is impossible
Rb
The element with the smallest first ionization energy is Francium, as it is located in Group 1 of the periodic table and has the largest atomic size. Among the elements listed, lithium (Li) would have the smallest first ionization energy as it is closer to the upper right of the periodic table compared to sodium (Na), potassium (K), and rubidium (Rb).
K (lowest) Na Li B N (highest)
Elements are ordered by increasing ionization energy based on their position in the periodic table. Ionization energy generally increases from left to right across a period and decreases from top to bottom within a group. This is because as you move across a period, the nuclear charge increases, resulting in a greater attraction for the valence electrons, while moving down a group the outer electrons are further from the nucleus and shielded by inner electrons, making them easier to remove.