It's carbon. The trend for 1st ionization energy is that it increases as you move left-to-right across a period. As you move in that direction across period 2, ionization energy increases, and since carbon is the most to the right, it has the highest 1st I.E.
The element that has the highest second ionization energy is Li. When you remove the first electron from Li you are down to the 1s orbital. They are harder to remove because they are closest to the nucleus.
The ionization energy of calcium (Ca) is the energy required to remove one electron from a neutral atom of calcium in the gaseous state. The first ionization energy of calcium is approximately 590.6 kJ/mol, indicating the energy needed to remove the outermost electron. Additional ionization energies are required to remove subsequent electrons.
Atoms of alkaline metals: Rb, Cs, Fr, K, Na, Li. They have a low ionization potential. This potential is expressed in kJ/mol - molar ionization energy and is different for the first, second, third...n electron.
The main group atom expected to have the lowest second ionization energy is typically found in Group 1 (alkali metals), particularly lithium (Li) or sodium (Na). This is because, after the removal of the first electron, these elements achieve a stable noble gas electron configuration, making it significantly easier to remove the second electron compared to other main group elements. The low effective nuclear charge felt by the remaining electrons in these atoms also contributes to their lower second ionization energy.
Because Be contains more protons and thus has greater nuclear positivity which exerts a stronger attraction for its electrons which requires more energy to remove one of the electrons leading to a higher ionization potential.
The element that has the highest second ionization energy is Li. When you remove the first electron from Li you are down to the 1s orbital. They are harder to remove because they are closest to the nucleus.
It is difficult to remove electron from He than Li. LI easily loses electron and reach stable state.
The element with the smallest first ionization energy is Francium, as it is located in Group 1 of the periodic table and has the largest atomic size. Among the elements listed, lithium (Li) would have the smallest first ionization energy as it is closer to the upper right of the periodic table compared to sodium (Na), potassium (K), and rubidium (Rb).
Rb
The ionization energy increases from Cs to K to Li. This is because as you move from left to right across a period in the periodic table, the effective nuclear charge increases, leading to a stronger attraction between the outer electrons and the nucleus, thus requiring more energy to remove an electron.
Lithium ====> Li , Electronic configuration { 1S2 2S1 } So we have only first ionization An the second will be from Complete stable energy level that need great amount of energy to remove it And that is impossible
The noble gases such as helium, neon, argon, and xenon typically have the highest ionization energies on the periodic table. This is because they have a full valence shell of electrons which makes it difficult to remove an electron.
The ionization energy of calcium (Ca) is the energy required to remove one electron from a neutral atom of calcium in the gaseous state. The first ionization energy of calcium is approximately 590.6 kJ/mol, indicating the energy needed to remove the outermost electron. Additional ionization energies are required to remove subsequent electrons.
Atoms of alkaline metals: Rb, Cs, Fr, K, Na, Li. They have a low ionization potential. This potential is expressed in kJ/mol - molar ionization energy and is different for the first, second, third...n electron.
1st ionization energy is the energy to remove one electron from a neutral atom. 2nd ionization energy is the energy to remove an electron from a positively charged ion. When this is done there is a stronger attraction for electrons in the ion than in the neutral atom because there is one less electron to 'interfere' with the electron being removed.
K (lowest) Na Li B N (highest)
The main group atom expected to have the lowest second ionization energy is typically found in Group 1 (alkali metals), particularly lithium (Li) or sodium (Na). This is because, after the removal of the first electron, these elements achieve a stable noble gas electron configuration, making it significantly easier to remove the second electron compared to other main group elements. The low effective nuclear charge felt by the remaining electrons in these atoms also contributes to their lower second ionization energy.