In the given scenario, the cathode is positive.
When water splits, hydrogen gas and oxygen gas are formed.
In the given scenario, the value of delta t is the difference between the final time and the initial time.
In the given scenario, the relationship between variables ka and kb is that they are inversely proportional. This means that as one variable increases, the other variable decreases, and vice versa.
In order that a substance can conduct an electric current, the electrical charge has to be able to move through the substance by means of charged particles. In metals, even when they are solid, the metal atoms split into ions and free electrons. These free electrons can move from atom to atom (or, more accurately ion to ion). Therefore, the electrical charge can be carried on these free moving electrons and the metal conducts the electricity. In solid sodium hydoxide, however, there are no free moving charged particles and so solid sodium hydroxide does not conduct. Add water, however, and the sodium hydroxide dissolves to form a solution. In the solution the sodium hydroxide splits into ions - positive sodium ions (Na+) and negative hydroxide ions (OH-) that are free to move about the solution. Therefore the electrical charge can be carried on these free moving particles and so the solution (but not the solid) conducts. If a current is passed through sodium hydroxide solution the Na+ ions are attracted to the negative cathode. Also, Hydrogen ions (H+) from the water are also attracted to the cathode. Because Hydrogen is less reactive than Sodium, it is discharged from the solution (rather than the sodium) so that hydrogen gas is given off. It does this because each Hydrogen ion (H+) can pick up an electron from the current flowing through the cathode to form a hydrogen atom (H). Two atoms will then join up to form a hydrogen molecule H2 which is discharged at the cathode forming hydrogen gas. Similarly in the solution the OH- ions are attracted to the positive anode. Also, Hydroxide ions (OH-) from the water are also attracted to the cathode. Each of the OH- ions deposits an electron to provide the current flowing through the anode. This forms an OH radical which, being unstable, joins with another OH radical formed to produce a water molecule H2O and an oxygen atom. When a pair of oxygen atoms are produced, they join up to form an oxygen molecule O2 which is discharged at the anode forming oxygen gas. Melted Sodium Hydroxide also conducts as the ions are again free to move around in the melted substance. In this case, oxygen is still given off at the anode, but, as there are no hydrogen ions in the liquid because there is no water present, Sodium metal is discharged at the cathode instead.
This observation indicates that cathode rays are independent of the material from which they originate, suggesting that they may consist of fundamental particles. This led to the discovery of electrons as components of cathode rays and was a significant step in the development of atomic theory.
To produce a spontaneous reaction in an electrochemical cell, the half-reaction at the anode must involve the oxidation of a species. If the cathode half-reaction is a reduction, such as the reduction of a metal ion to its elemental form, the corresponding anode half-reaction could be the oxidation of that metal to its ion. For example, if the cathode reaction is ( \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu} ), the anode reaction could be ( \text{Zn} \rightarrow \text{Zn}^{2+} + 2e^- ), where zinc is oxidized to provide electrons for the reduction at the cathode.
Goldstien performed discharge tube experiments in which he used perforated cathode and gas at a very low pressure after passing high current between the electrodes it was found that some rays were coming from the sides of cathode, which passed through the holes in anode and produce a green flouresense on the opposite sides wall coated with zinc sulphide.These rays were called as anode rays.They were contaning positive charge.Goldstien named them protons. This answer was given by facebook/danish rashid bhat.He lives in,nawa, bonigam
In science, a battery is a device that stores chemical energy and converts it into electrical energy through an electrochemical reaction. Batteries consist of one or more electrochemical cells, each of which contains two electrodes - an anode and a cathode - separated by an electrolyte. When a circuit is connected to the battery, electrons flow from the negative terminal (anode) to the positive terminal (cathode), generating an electric current.
There must be hundreds of them, given that the electroplating process requires that the anode and cathode be in the liquid being used.
In the given scenario, light is visible.
What are the steps in staffing that you observed in the given scenario
When water splits, hydrogen gas and oxygen gas are formed.
In that given scenario, the possible blood types of the child are: A-, A+, O+ and O-.So Yes, it is possible to have a child with A positive with 25%.
-0.3 v to 0.7 v (- 0.3 is used in the tv signal to erase the line for new ones 0,7 is white color in a tv) tolal -03 to 0,7 = 1 volt
The half reactions are Al+3 + 3 e- -> Al (at the cathode) and 2 Cl-1 -> Cl2 + 2 e- at the anode. Applying the proper integers by which to multiply the half reactions so that the number of electrons received at the cathode equals the number of electrons given up at the anode gives an overall reaction of 2 Al+3 + 6 Cl-1 -> 2 Al + 3 Cl2.
You do not mention what you are using as the anode and cathode, but i would assume that given the green colour you are using copper or brass perhaps as the anode, and it is breaking down into a copper carbonate(which is green). By applying electrical current to the circuit you are speeding up the conversion of copper to copper carbonate(or similar).
The final charge on C2 in the scenario is 2.