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How many milliliters of 0.103 M HCl would be required to titrate 6.46 g KOH?
6.46g(KOH) / 56.108 g/mol(KOH) = 0.1151 mol(KOH) = 0.1151 mol(OH-) , which needs of the titrant the same amount of acid, so:0.1151 mol H+ = 0.1151 mol(HCl) / 0.103 mol(HCl)/L(titrant) = 1.118 L of this titrant ( 0.103 M HCl)= 1118 ml
.45g of hydrochloric acid is dissolved in water to make 3.5l of solution what is the pH of HCl?
The pH of a solution of HCl is calculated using the concentration of H+ ions. Since HCl dissociates completely in water, the concentration of H+ ions is equal to the concentration of HCl. First, calculate the concentration of HCl in the solution: 0.45g HCl / (36.46 g/mol) = 0.012 mol HCl. Then, divide the moles of HCl by the volume of the solution in liters to get the concentration in mol/L. Finally, calculate the pH using the formula pH = -log[H+].
What mass of NaHCO3 would be needed to neutralize a spill consisting of 12.5 mL of 5.0 M HCl?
12.5 mL * 5.0 (m)mol/(m)L HCl = 62.5 mmol spilled HClneeds62.5 mmol NaHCO3 = 62.5 mmol * 84.01 (m)g/(m)mol NaHCO3 = 5250 mg NaHCO3 = 5.25 g pure NaHCO3
How many moles of solute are in 50 mL of a 12 M HCl solution?
To find the number of moles of solute in the solution, first, calculate the amount of HCl in grams using the formula: moles = molarity x volume (in liters). Then, convert the grams of HCl to moles by dividing by the molar mass of HCl (36.46 g/mol).
If 5.00 ml of hcl requires 4.76 ml of 0.9581 m naoh to just consume the hcl what is the concentration of the hcl?
The equation you need is:M1*V1=M2*V2V1= 5 ml HCLV2= 4.76mL NaOHM2= 0.9581M1= M2*V2/M1Plug your numbers into the equation and you'll be done.
What is the pH of a 1.8 x 10-5 M HCl Solution?
25g HCl 1 mol 36.46g HCl =.686 mol M=.686 mol/1.5 L=.457M pH= -log(.457) pH= .34
How many moles of HCl are presented in 0.70 L of a 0.33 M HCl solution?
c * V = 0.33 (mol/L) * 0.70 (L) = 0.231 = 0.23 mol HCl
How many moles of HCl are present in 0.70 L of a 0.33 M HCl solution?
c * V = 0.33 (mol/L) * 0.70 (L) = 0.231 = 0.23 mol HCl
How many milliliters of 0.103 M HCl would be required to titrate 6.46 g KOH?
6.46g(KOH) / 56.108 g/mol(KOH) = 0.1151 mol(KOH) = 0.1151 mol(OH-) , which needs of the titrant the same amount of acid, so:0.1151 mol H+ = 0.1151 mol(HCl) / 0.103 mol(HCl)/L(titrant) = 1.118 L of this titrant ( 0.103 M HCl)= 1118 ml
.45g of hydrochloric acid is dissolved in water to make 3.5l of solution what is the pH of HCl?
The pH of a solution of HCl is calculated using the concentration of H+ ions. Since HCl dissociates completely in water, the concentration of H+ ions is equal to the concentration of HCl. First, calculate the concentration of HCl in the solution: 0.45g HCl / (36.46 g/mol) = 0.012 mol HCl. Then, divide the moles of HCl by the volume of the solution in liters to get the concentration in mol/L. Finally, calculate the pH using the formula pH = -log[H+].
What mass of NaHCO3 would be needed to neutralize a spill consisting of 12.5 mL of 5.0 M HCl?
12.5 mL * 5.0 (m)mol/(m)L HCl = 62.5 mmol spilled HClneeds62.5 mmol NaHCO3 = 62.5 mmol * 84.01 (m)g/(m)mol NaHCO3 = 5250 mg NaHCO3 = 5.25 g pure NaHCO3
How many moles of solute are in 50 mL of a 12 M HCl solution?
To find the number of moles of solute in the solution, first, calculate the amount of HCl in grams using the formula: moles = molarity x volume (in liters). Then, convert the grams of HCl to moles by dividing by the molar mass of HCl (36.46 g/mol).
If 5.00 ml of hcl requires 4.76 ml of 0.9581 m naoh to just consume the hcl what is the concentration of the hcl?
The equation you need is:M1*V1=M2*V2V1= 5 ml HCLV2= 4.76mL NaOHM2= 0.9581M1= M2*V2/M1Plug your numbers into the equation and you'll be done.
How many grams of HCl are contained in 4.25mL of a 0.405M aqueous solution of HCl?
M * V = n 0.405 M * 0.00425 ml = 0.00172125 mole of HCl The molar mass of HCl is: 1.007947 + 35.453 = 36.460947 g/mole m = mm * n So the mass in gram is: 36.460947 g/mole * 0.00172125 mole = 0.0628 gram
How many moles of HCl are dissolved in 2.0 L of 0.25 M HCl solution?
0.5 Moles If you have a 0.25 M solution, you have 0.25 mol/dm3, or 0.25 moles in 1 L (0.25 mol/L) If you have 2 L of solution, you have 2 L x 0.25 mol/L = 0.5 mol The L's cancel out, and you're left with moles.
How many moles of HCl are in 50 ml of 4.0 M HCl?
To find the moles of HCl, first calculate the millimoles of HCl in 50 mL: 4.0 mol/L * 50 mL = 200 mmol. Then convert millimoles to moles by dividing by 1000: 200 mmol / 1000 = 0.2 moles of HCl. Therefore, there are 0.2 moles of HCl in 50 mL of 4.0 M HCl.
What is the molarity of a HCI solution that contains 10.0 g of HCI in 250 mL of solution?
To find the molarity, first calculate the number of moles of HCl using its molecular weight (36.46 g/mol). The number of moles is 10.0 g / 36.46 g/mol = 0.274 moles. Then, divide the number of moles by the volume of the solution in liters (250 mL = 0.25 L) to get the molarity: 0.274 moles / 0.25 L = 1.096 M. Thus, the molarity of the HCl solution is 1.096 M.
