17 grams is 17,000 milligrams.
17g (nitrogen = 14)+(3 x hydrogen 1 = 3) = 3 + 17 = 17g
To find out how many grams are dissolved in 450mL, you can use a proportion based on the given information. The drug concentration is 17g/100mL, so you can set up the proportion: 17g/100mL = x/450mL. Cross multiply and solve for x to find the amount of drug dissolved in 450mL.
17g/mol to calculate it out. you have to times the Average atomic mass (amu) but the amount of atoms. so nitrogen: 14*1 and hydrogen: 1*3. then add them together. it comes out to 17, so you put that into g/mol. and there you have 17g/mol.
The difference between 0.05mg and 0.075mg is 0.025mg. This means that 0.075mg is a higher dose than 0.05mg by 0.025mg. The numerical value represents the amount of medication in milligrams.
Molarity = moles of solute/Liters of solution need to find moles NH3 16.7 grams NH3 (1 mole NH3/17.034 grams) = 0.9804 moles NH3 --------------------------------now Molarity = 0.9804 moles NH3/1.50 Liters = 0.654 M -------------
The answer is no .05mg is the same as saying .050mg, .125mg is not smaller than .05mg.
No.
1g = 1000mg 17g x 1000mg/g = 17000mg
NAY
I'm almost sure it would be 18g or 17g to the second power
To find the percent of 17g sucrose in 188g of water, first calculate the total mass: 17g (sucrose) + 188g (water) = 205g. Then, divide the mass of sucrose (17g) by the total mass (205g), and multiply by 100 to convert to a percentage. The percent of 17g sucrose in 188g of water would be roughly 8.29%.
17g
17g/mol
To find the percentage of 17g of sucrose in 188g of water, first calculate the total weight by summing both amounts (17g + 188g = 205g). Then, divide the weight of the sucrose by the total weight and multiply by 100 to get the percentage: (17g / 205g) * 100 ≈ 8.29%.
11 to 17g of sugar, its high
well, just about 17g.
The famous B-17G had a full crew of 10. -Pilot, co-pilot, navigator, bombardier, radio operator, and 5 gunners.