The percent, by weight of 17g of sucrose in 188g of water is calculated as follows
Mass of Sucrose / Total Mass of Solution *100%
= 17 / (188 + 17) * 100 = 8.29%
To find the percent of 17g sucrose in 188g of water, first calculate the total mass: 17g (sucrose) + 188g (water) = 205g. Then, divide the mass of sucrose (17g) by the total mass (205g), and multiply by 100 to convert to a percentage. The percent of 17g sucrose in 188g of water would be roughly 8.29%.
The simple beginning is that the definition of a calorie is "the energy required to raise the temperature of 1g of water 1°C." Therefore, the energy required to raise 17g of water 32°C: 17*32=544 cal. However, the question asked about ice. There is an extra bit of energy required for the change of physical state. The energy required to convert 1 gram of ice at 0°C to liquid water at 0°C is called the "latent heat" and is equal to about 80 cal. To convert 17g of ice, we multiply this together: 17g * 80cal/g = 1360 cal. So, we add this energy required for the change of state to the energy required to raise the listed quantity to the required temperature and we get 544 cal + 1360 cal = 1904 cal, assuming no heat is lost to the environment. I hope this clarifies some things.
The weight of obsidian is approximately 2.3 to 2.6 grams per cubic centimeter.
Since Density is equal to mass divided by Volume... D=M/V Then... The density would equal 5.667 g/cm3
True, the balanced equation N2 + 3H2 -> 2NH3 shows that 1 mole of N2 reacts with 3 moles of H2 to form 2 moles of NH3. From the molar masses of N2 (28g/mol), H2 (2g/mol), and NH3 (17g/mol), it can be calculated that 1g of N2 reacts with 3g of H2 to form 2g of NH3.
To find the percent of 17g sucrose in 188g of water, first calculate the total mass: 17g (sucrose) + 188g (water) = 205g. Then, divide the mass of sucrose (17g) by the total mass (205g), and multiply by 100 to convert to a percentage. The percent of 17g sucrose in 188g of water would be roughly 8.29%.
Molarity=[w/GMW]*[1000/volume(in mL)] 0.5=[w/342]*[1000/100]=17.1g similarly,34.2g sucrose is to dissolved in water and made up to 100mL to make 1molar solution and 171g to make 5molar solution.
No, 17g is equal to 17,000mg. 0.5mg is much smaller than 17g.
1g = 1000mg 17g x 1000mg/g = 17000mg
I'm almost sure it would be 18g or 17g to the second power
17g
17g/mol
11 to 17g of sugar, its high
well, just about 17g.
The famous B-17G had a full crew of 10. -Pilot, co-pilot, navigator, bombardier, radio operator, and 5 gunners.
The simple beginning is that the definition of a calorie is "the energy required to raise the temperature of 1g of water 1°C." Therefore, the energy required to raise 17g of water 32°C: 17*32=544 cal. However, the question asked about ice. There is an extra bit of energy required for the change of physical state. The energy required to convert 1 gram of ice at 0°C to liquid water at 0°C is called the "latent heat" and is equal to about 80 cal. To convert 17g of ice, we multiply this together: 17g * 80cal/g = 1360 cal. So, we add this energy required for the change of state to the energy required to raise the listed quantity to the required temperature and we get 544 cal + 1360 cal = 1904 cal, assuming no heat is lost to the environment. I hope this clarifies some things.
How many teaspoons is 17 g