most silver compounds have low solubility.
AgF is soluble in water, because Fluorine is very electronegative.(Electronegativy is the tendancy to attract the bonding electrons in a covalent bond.) Water is a polar molecule, which means that for a compound to be soluble, it must also be polar. As fluorine is the most electronegative out of all the elements, it makes the AgF molecule slightly polar, which makes it soluble in water. Chlorine, Bromine and Iodine are not as electronegative, therefore they don't create a polar molecule. They instead form precipitates.AgBr is the chemical formula of silver bromide.
The chemical formula for silver bromide is AgBr.
Silver bromide (AgBr) is a light yellowish precipitate.
Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] First check that the given equation is balanced ... it isn't ... so the first thing to do is balance the equation: balancing Na: 2Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] and everything is now balanced so we've got the balanced equation molar mass AgBr = 107.87 + 79.90 = 187.77 g/mol mol AgBr available = 42.7 g AgBr x [1 mol / 187.77 g] = 0.2274 mol AgBr from the balanced equation the mole ratio AgBr : Na2S2O3 = 1 : 2 so mol Na2S2O3 required = 0.2274 mol AgBr x [ 2 mol Na2S2O3 / mol AgBr] = 0.455 mol Na2S2O3 (to 3 sig figs)
Silver bromide.
Silver bromide (AgBr) is not soluble in sodium hydroxide (NaOH). It is a poorly soluble salt, and while NaOH can dissolve some silver compounds, AgBr remains largely insoluble in this alkaline solution. However, AgBr can be converted into soluble silver complexes under certain conditions, but that typically requires the presence of complexing agents rather than just NaOH.
To determine the weight of AgBr that dissolves in 200 mL of 100 M NaCN, we first need to consider the solubility equilibrium involving AgBr and the complexation reaction with NaCN, which forms soluble complexes like [Ag(CN)2]⁻. However, since AgBr is a sparingly soluble salt, its solubility in such a concentrated NaCN solution will be significantly increased. The exact weight can be calculated if the solubility product (Ksp) of AgBr and the stability constant for the complexation with CN⁻ are known, but typically, the presence of NaCN would allow for a substantial amount of AgBr to dissolve due to complexation.
AgBr is the chemical formula of silver bromide.
The chemical formula for silver bromide is AgBr.
AgBr is the chemical formula (not symbol) of silver bromide.
Образуется растворимое комплексное соединение: AgBr + 2 NH4OH -----> [Ag(NH3)2]+ + Cl- + 2 H2O.
Silver bromide (AgBr) is a light yellowish precipitate.
Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] First check that the given equation is balanced ... it isn't ... so the first thing to do is balance the equation: balancing Na: 2Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] and everything is now balanced so we've got the balanced equation molar mass AgBr = 107.87 + 79.90 = 187.77 g/mol mol AgBr available = 42.7 g AgBr x [1 mol / 187.77 g] = 0.2274 mol AgBr from the balanced equation the mole ratio AgBr : Na2S2O3 = 1 : 2 so mol Na2S2O3 required = 0.2274 mol AgBr x [ 2 mol Na2S2O3 / mol AgBr] = 0.455 mol Na2S2O3 (to 3 sig figs)
Silver bromide.
AgBr is a compound composed of silver (Ag) and bromine (Br) elements.
Silver will have a +1 and bromate is -1 so they combine in a 1:1 ratio. The formula would be AgBrO3.
Yes, AgBr is a solid. It is a white crystalline solid that is insoluble in water.