CH3Br is a covalent compound because the atoms reacting are all non-metals.
Ionic compounds are generally formed from a non-metal reacting with a metal.
The bond angle in a molecule containing a CH3Br group is approximately 109.5 degrees.
CH3Br is a nonpolar molecule. Although the C-Br bond is polar due to the electronegativity difference between carbon and bromine, the overall molecule is nonpolar because of its symmetrical tetrahedral molecular geometry.
There are four covalent bonds in CH3Br: one carbon-bromine bond and three carbon-hydrogen bonds.
Barium bromide (BaBr2) dissolves well in water and is toxic in aqueous solution.
The reason ch3br or ch3f have higher boiling points compared to other compounds is because they have stronger intermolecular forces due to the presence of hydrogen bonding.
The bond angle in a molecule containing a CH3Br group is approximately 109.5 degrees.
CH3Br is a nonpolar molecule. Although the C-Br bond is polar due to the electronegativity difference between carbon and bromine, the overall molecule is nonpolar because of its symmetrical tetrahedral molecular geometry.
The bromide ion is Br-. A bromide is a chemical compound where bromine is the most electronegative element. It may be ionic and contain the bromide ion, Br- or covalent like methyl bromide, CH3Br.
There are four covalent bonds in CH3Br: one carbon-bromine bond and three carbon-hydrogen bonds.
CH4 + Br2 --> CH3Br + HBr
Barium bromide (BaBr2) dissolves well in water and is toxic in aqueous solution.
The reaction between methane and bromine in the presence of sunlight results in the substitution of one hydrogen atom in methane with a bromine atom, yielding bromomethane (CH3Br). The equation for this reaction is: CH4 + Br2 → CH3Br + HBr.
The reason ch3br or ch3f have higher boiling points compared to other compounds is because they have stronger intermolecular forces due to the presence of hydrogen bonding.
Methyl bromide has a chemical formula of CH3Br. It consists of a carbon atom bonded to three hydrogen atoms and one bromine atom. The molecule has a tetrahedral shape with a polar covalent bond between carbon and bromine.
The reaction between CH4 (methane) and Br2 (bromine) would result in the substitution of one hydrogen atom in methane with a bromine atom, forming bromomethane (CH3Br) and hydrogen bromide (HBr).
The molar mass of bromomethane (CH3Br) is approximately 94.94 g/mol.
CH3Br is a polar molecule due to the differences in electronegativity between carbon, hydrogen, and bromine atoms. The unequal sharing of electrons creates a partial positive charge on hydrogen atoms and a partial negative charge on bromine atom, resulting in a net dipole moment.