CH4 + Br2 = CH3Br + HBr
The product of the following reaction Cs Br2 is CsBr.
I have no idea what you mean by "most correct product", but assuming that there is sufficient (excess) chlorine, you get lithium chloride and elemental bromine For A plus 2LiCl + Br2
The product in the reaction of CH4 + 2O2 => CO2 + 2H2O is carbon dioxide (CO2) and water (H2O).
AIBr3(s)
1 mole Br2 = 159.808g Br2 = 6.022 x 1023 molecules Br2 4.89 x 1020 molecules Br2 x 1mol Br2/6.022 x 1023 molecules Br2 x 159.808g Br2/mol Br2 = 0.130g Br2
C6H6O + Br2
The product of the following reaction Cs Br2 is CsBr.
Methane + Bromine --> Bromomethane + Hydrogen bromide
CH4 + Br2 --> CH3Br + HBr
It produces Bromomethane and Hydrogen Bromide Equation: CH4 + Br2 ----> CH3Br + HBr
CH4(g) + Br2(g) -----------------> CH3Br(g) + HBr(g) (sunlight/UV Light)
I have no idea what you mean by "most correct product", but assuming that there is sufficient (excess) chlorine, you get lithium chloride and elemental bromine For A plus 2LiCl + Br2
The product in the reaction of CH4 + 2O2 => CO2 + 2H2O is carbon dioxide (CO2) and water (H2O).
ch4 + 2o2 → co2 + 2h2o
AIBr3(s)
The reactions of Group 1 elements with Br2 are very vigorous. For example, Sodium it would go 2Na + Br2 = 2 NaBr.
1 mole Br2 = 159.808g Br2 = 6.022 x 1023 molecules Br2 4.89 x 1020 molecules Br2 x 1mol Br2/6.022 x 1023 molecules Br2 x 159.808g Br2/mol Br2 = 0.130g Br2