CH4 + Br2 = CH3Br + HBr
In the absence of sunlight, methane (CH4) will react with bromine (Br2) to form bromomethane (CH3Br) and hydrogen bromide (HBr) as products. The balanced chemical equation for this reaction is CH4 + Br2 -> CH3Br + HBr.
The product of the following reaction Cs Br2 is CsBr.
The most correct product formed from the reaction of LiBr + Cl2 is LiCl + Br2. This is because lithium chloride (LiCl) and bromine (Br2) are the expected products when lithium bromide (LiBr) reacts with chlorine (Cl2) in a single displacement reaction.
The product in the reaction of CH4 + 2O2 => CO2 + 2H2O is carbon dioxide (CO2) and water (H2O).
The balanced chemical equation is 2HBr + H2 + Br2 + N2O → N2 + O2 + HBr + H2 + Br2. The equation provided in your question doesn't appear to balance correctly, so I attempted to balance it based on the chemical species presented. It's essential to ensure that the number of atoms of each element is the same on both sides of the equation.
CH4 + Br2 --> CH3Br + HBr
In the absence of sunlight, methane (CH4) will react with bromine (Br2) to form bromomethane (CH3Br) and hydrogen bromide (HBr) as products. The balanced chemical equation for this reaction is CH4 + Br2 -> CH3Br + HBr.
The product of the following reaction Cs Br2 is CsBr.
The most correct product formed from the reaction of LiBr + Cl2 is LiCl + Br2. This is because lithium chloride (LiCl) and bromine (Br2) are the expected products when lithium bromide (LiBr) reacts with chlorine (Cl2) in a single displacement reaction.
The equation represents the reaction between methane (CH4) and bromine (Br2) to form methyl bromide (CH3Br) and hydrogen bromide (HBr). This reaction is a substitution reaction in which a hydrogen atom in methane is replaced by a bromine atom.
The reaction between methane and bromine in the presence of sunlight results in the substitution of one hydrogen atom in methane with a bromine atom, yielding bromomethane (CH3Br). The equation for this reaction is: CH4 + Br2 → CH3Br + HBr.
When benzaldehyde (C6H6O) is mixed with Br2, the benzene ring undergoes electrophilic aromatic substitution where one of the hydrogen atoms on the ring is substituted by a bromine atom. This reaction results in the formation of bromobenzene (C6H5Br).
ch4 + 2o2 → co2 + 2h2o
The reactants for the reaction involving Li and Br2 are lithium (Li) and bromine (Br2). The product of this reaction is lithium bromide (LiBr). In this reaction, lithium combines with diatomic bromine to form the ionic compound lithium bromide.
The product in the reaction of CH4 + 2O2 => CO2 + 2H2O is carbon dioxide (CO2) and water (H2O).
CH4 + 2O2 --> CO2 + 2(H2O), the products are CO2 and H2O
The balanced chemical equation is 2HBr + H2 + Br2 + N2O → N2 + O2 + HBr + H2 + Br2. The equation provided in your question doesn't appear to balance correctly, so I attempted to balance it based on the chemical species presented. It's essential to ensure that the number of atoms of each element is the same on both sides of the equation.