The reactants for the reaction involving Li and Br2 are lithium (Li) and bromine (Br2). The product of this reaction is lithium bromide (LiBr). In this reaction, lithium combines with diatomic bromine to form the ionic compound lithium bromide.
Li is Metal why Br is Non Metal
Lithium bromide (LiBr) is a compound that consists of two ions: lithium (Li⁺) and bromide (Br⁻). In this context, lithium acts as a cation, while bromide is the anion. Therefore, lithium bromide itself is not classified as either an anion or a cation; it is an ionic compound made up of both types of ions.
To determine the freezing point depression of a solution, we can use the formula: ΔTf = i * Kf * m, where ΔTf is the freezing point depression, i is the van 't Hoff factor (which is 2 for LiBr because it dissociates into Li⁺ and Br⁻), Kf is the freezing point depression constant for water (approximately 1.86 °C kg/mol), and m is the molality of the solution. First, we calculate the molality: 0.5 mol of LiBr in 0.5 kg of water (since 500 ml of water has a mass of about 0.5 kg) gives a molality of 1 mol/kg. Therefore, ΔTf = 2 * 1.86 °C kg/mol * 1 mol/kg = 3.72 °C. The freezing point of pure water is 0 °C, so the freezing point of the solution would be approximately -3.72 °C.
1 mole Li = 6.94g Li = 6.022 x 1023 atoms Li 27.0g Li x 6.022 x 1023 atoms Li/6.94g Li = 2.34 x 1024 atoms Li
lithium is Li
Lithium bromide (LiBr) is a compound, not a cation. The cation is Li+.
The oxidation number of Li in LiBr is +1, and the oxidation number of Br is -1.
The balanced chemical equation for the reaction is: 2Li + Br2 -> 2LiBr. To find the limiting reactant, we convert the given masses to moles, determine the mole ratio from the balanced equation, and compare the actual mole ratio of the reactants to the required mole ratio.
(7.6g LiBr)/(86.84g/mol) x (1molLi/1molBr) = .0875 mol Li or with sig figs, .088
Li is Metal why Br is Non Metal
The formula for lithium bromide is LiBr. The compound has a molar mass of 86.845 grams per mole. One of its main uses is as a desiccant.
Yes, LiBr (lithium bromide) is an ionic solid. It consists of lithium cations (Li+) and bromide anions (Br-) held together by ionic bonds.
Lithium metal when burned in air would form Lithium Oxide.2Li (s) + O2 (g) --> Li2O (aq)
Yes, LiBr (lithium bromide) is an ionic compound. It is formed by the transfer of an electron from lithium (Li) to bromine (Br), resulting in the formation of Li+ cation and Br- anion, held together by electrostatic forces.
LiBr= Lithium bromide==================an ionic compound
LiBr would be classified as ionic because it is formed between a metal (Li) and a non-metal (Br). Ionic bonds are formed when there is a transfer of electrons from the metal to the non-metal, resulting in the formation of positively charged cations (Li+) and negatively charged anions (Br-).
The compound formula LiBr stands for lithium bromide. It is a salt that is composed of lithium cations (Li+) and bromide anions (Br-).