CO2 plus H2O makes club soda - which is not a combustion.
The combustion reaction of heptane is:C7H16 + 11 O2 = 7 CO2 + 8 H2O
The balanced equation for the combustion reaction C5H8 + 5 O2 → 5 CO2 + 4 H2O.
C5h8 + 7o2 --> 5co2 + 4h2o
The unbalanced combustion reaction of C4H10(g) with O2(g) produces CO2(g) and H2O(g) as products. The balanced reaction is: C4H10(g) + O2(g) → CO2(g) + H2O(g)
This is a balanced chemical equation for the combustion of ethanol (C2H5OH) in the presence of oxygen (O2) to form carbon dioxide (CO2) and water (H2O): C2H5OH + 3O2 → 2CO2 + 3H2O
The combustion reaction of heptane is:C7H16 + 11 O2 = 7 CO2 + 8 H2O
Combustion reaction
C5h8 + 7o2 --> 5co2 + 4h2o
The balanced equation for the combustion reaction C5H8 + 5 O2 → 5 CO2 + 4 H2O.
No its a combustion reaction, not a double replacement
The reaction you've provided is a combustion reaction. In this reaction, methane (CH4) reacts with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) as products.
When C28H58 reacts with O2, it undergoes combustion to produce carbon dioxide (CO2) and water (H2O) as the combustion products.
As with any combustion reaction you need to include oxygen. The full equation for methanol combustion is: CH3OH + 2 O2 --> CO2 + 2 H2O
The chemical equation CO + H2O → CO2 + H2 represents the combustion of carbon monoxide (CO) with water (H2O) to produce carbon dioxide (CO2) and hydrogen gas (H2). This reaction releases energy in the form of heat.
The unbalanced combustion reaction of C4H10(g) with O2(g) produces CO2(g) and H2O(g) as products. The balanced reaction is: C4H10(g) + O2(g) → CO2(g) + H2O(g)
Hydrocarbons such as methane burning in oxygen is an example of oxidation and also combustion.
I assume you were looking to balance the reaction: CH4 + 2O2 --> CO2 +2H2O