Yes i believe that this is
when u break up CuCl2 in H2O
then you will end up with Cu(OH)2 and HCL
so basically, after you balance the equation
you end up with
CuCl2+H2O------>Cu(OH)2+2HCl
there are 3 rules you should know
1) salt of strong acid + strong base = neutral solution
2) salt of strong base + weak acid = basic solution
3) salt of strong acid + weak base = acidic solution
since Cu(OH)2 is a weak base
and HCL is strong acid
we have the rule number 3
so its acidic
CuCO3 is an salt that is not soluble
Yes, copper carbonate is ionic.
yes
2HCL+CuCO3---> CuCl2_H2O_CO2
CuCO3 is copper carbonate.
CuCO3 + H2SO4 = CuSO4 + H2O + CO2 Its already balanced
2 HNO3 + CuCO3 --> H2O + CO2 + Cu(NO3)2
Copper sulphate, carbon dioxide and water. CuCO3+H2SO4=CuSO4+CO2+H2O
2HCL+CuCO3---> CuCl2_H2O_CO2
Hydrochloric acid CuCO3 + 2HCl --> CuCl2 + CO2 + H2O
CuCO3 is copper carbonate.
CuCO3 + H2SO4 = CuSO4 + H2O + CO2 Its already balanced
2 HNO3 + CuCO3 --> H2O + CO2 + Cu(NO3)2
CuCO3 cathode: Cu2+ + 2 e- = Cu anode: H2O = 2H+ + 2e- + 0,5 O2 H2SO4 cathode: 2 H+ + 2e- = H2 anode: H2O = 2H+ + 2e- + 0,5 O2
Copper sulphate, carbon dioxide and water. CuCO3+H2SO4=CuSO4+CO2+H2O
12.5 (g CuCO3) = [12.5 (g CuCO3) / 123.555 (g/mol CuCO3)] = 0.1012 (mol CuCO3)0.1012 (mol CuCO3)* [1 (mol CuO) / (mol CuCO3)] = 0.1012 (mol CuO)= [0.1012 (mol CuO) * 79.545 (g/mol CuO)] = 8.047 g CuO = 8.05 g CuO
No, CuCO3, or copper carbonate is a compound made up of an element and a polyatomic ion.
Copper carbonate + Hydrochloric acid ----->Copper chloride + Carbonic acid. CuCO3(aq) + 2HCl(aq)-------->CuCl2(aq) + H2CO3 (aq) Carbonic acid splits to form water and carbon dioxide. H2CO3 (aq)--------> H2O (l) + CO2 (aq) So the reaction could also be written as: CuCO3(aq) + 2HCl(aq)-------->CuCl2(aq) + H2O (l) + CO2 (aq) This type of a reaction is known as a single displacement reaction.
Heating CuCO3 (copper (II) carbonate) produces carbon dioxide (CO2) and copper oxide (CuO).
CuCO3 + H2SO4 --> CuSO4 + CO2 + H2OThe products are a salt, copper sulfate, carbon dioxide gas and water.