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Yes i believe that this is

when u break up CuCl2 in H2O

then you will end up with Cu(OH)2 and HCL

so basically, after you balance the equation

you end up with

CuCl2+H2O------>Cu(OH)2+2HCl

there are 3 rules you should know

1) salt of strong acid + strong base = neutral solution

2) salt of strong base + weak acid = basic solution

3) salt of strong acid + weak base = acidic solution

since Cu(OH)2 is a weak base

and HCL is strong acid

we have the rule number 3

so its acidic

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14y ago

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