Yes OH is in fact a Bronsted base making H3O a acid
Ammonia (NH3) --> can become NH2- or NH4+ Water (H2O) --> can become OH- or H3O+
It is a Bronsted-Lowery base because the carbonyl oxygens will readily accept a proton.
Oh, dude, HCO3 is like that ultimate multitasker in the chemistry world. It can totally be a Bronsted acid or base depending on the situation. So yeah, it's like a chameleon of the chemical world, just doing its thing, not caring too much about labels.
An equation demonstrating Bronsted-Lowry acid-base properties can be written as HA + B -> A- + HB+, where HA is the acid donating a proton (H+), B is the base accepting the proton, A- is the conjugate base formed by the acid losing the proton, and HB+ is the conjugate acid formed by the base accepting the proton. This equation shows the transfer of a proton from an acid to a base, following the Bronsted-Lowry definition of acids and bases.
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Ammonia (NH3) --> can become NH2- or NH4+ Water (H2O) --> can become OH- or H3O+
This is a Bronsted question. Hs- is the acid in this which makes H2O a base. Therefore S-2 is the conjugate base and the H3O+ hydronium ion is the conjugate acid.
There are Bronsted-Lowry bases and Lewis bases... Brønsted bases accept protons (H+) and Lewis bases donate electrons... So something like H2O + H2O--> H3O (hydronium) + -OH would mean that H2O is a Bronsted base and acid. You have to look at it in context.
It is a Bronsted-Lowery base because the carbonyl oxygens will readily accept a proton.
Oh, dude, HCO3 is like that ultimate multitasker in the chemistry world. It can totally be a Bronsted acid or base depending on the situation. So yeah, it's like a chameleon of the chemical world, just doing its thing, not caring too much about labels.
An equation demonstrating Bronsted-Lowry acid-base properties can be written as HA + B -> A- + HB+, where HA is the acid donating a proton (H+), B is the base accepting the proton, A- is the conjugate base formed by the acid losing the proton, and HB+ is the conjugate acid formed by the base accepting the proton. This equation shows the transfer of a proton from an acid to a base, following the Bronsted-Lowry definition of acids and bases.
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Because a bronsted-lowry acid donates proton such as ( H+ ) and water can donate H+ such as ( H2O + NH3 ---> NH4+ + OH- ) here water donated H+ to ammonia to produce NH4 ( which is an acid )
H2O can act as both a Brønsted-Lowry acid and base. As an acid, it can donate a proton by giving away a hydrogen ion. As a base, it can accept a proton by taking on a hydrogen ion. This makes H2O amphiprotic.
In the reaction, HBr donates a proton (H+) to H2O, making HBr the acid and H2O the base. The resulting products are Br- (conjugate base of HBr) and H3O+ (conjugate acid of H2O).
The Bronsted-Lowry definition describes acids as being proton (H+) donators and bases as being proton acceptors. So the answer would be C, because the carbonate anion is accepting a proton (H+ cation) to become the HCO3-
Such organic species are alcohols and inorganic species include bicarbonate, bisulphate and biphosphate ions.