Sodium sulfate is a neutral (or very weakly basic) salt.
yes although, technically it isn't even considered basic because there are no OH- ions... if it read NaOH it would be a strong base because the Na+ and OH- ions dissosociate completely so it is can be considered a weak base because it isn't a strong base.
The balanced chemical equation for the reaction between Na2SO3 (sodium sulfite) and HCl (hydrochloric acid) is: Na2SO3 + 2HCl -> 2NaCl + H2O + SO2
The formula is Na2SO3 , because Na have 1 valence electrone and SO3 is a polyatomic with 2 valence electrons so u cross multiply Na1 * SO3(2) =Na2SO3
Na2SO3(aq) + 2HCl(aq) ---> 2NaCl(aq) + SO2(g) + H2O(l)
2 NaOH + SO2 = H2O + Na2SO3
yes although, technically it isn't even considered basic because there are no OH- ions... if it read NaOH it would be a strong base because the Na+ and OH- ions dissosociate completely so it is can be considered a weak base because it isn't a strong base.
The balanced chemical equation for the reaction between Na2SO3 (sodium sulfite) and HCl (hydrochloric acid) is: Na2SO3 + 2HCl -> 2NaCl + H2O + SO2
The formula is Na2SO3 , because Na have 1 valence electrone and SO3 is a polyatomic with 2 valence electrons so u cross multiply Na1 * SO3(2) =Na2SO3
Na2SO3(aq) + 2HCl(aq) ---> 2NaCl(aq) + SO2(g) + H2O(l)
Na2SO3.
2 NaOH + SO2 = H2O + Na2SO3
The oxidation number of Na in Na2SO3 is +1, the oxidation number for S in SO3 is +4, and the oxidation number for O in SO3 is -2.
Supposed you mean an aqueous solution of Na2SO3 , you will find in it the following ions:Na+SO32-very small amount of HSO3- (from the 'weak base' reaction with water: OH- is also formed)
Na2SO3 is a chemical compound created by the synthesis of sodium and the sulfite molecule. This gives it its name of sodium sulfite.
The empirical formula for sodium sulfite is Na2SO3. This formula represents the simplest whole number ratio of atoms of each element in the compound.
sodium sulfite is soluble in water...though it may partially reacts to liberate SO2 gas and it can make the water acidic too Na2SO3 + H2O → 2NaOH + SO2 (only partial) But in acidic medium it decomposes as Na2SO3 + 2 H+ → 2 Na+ + H2O + SO2
The chemical reaction between acetic acid (CH3COOH) and sodium sulfite (Na2SO3) results in the formation of sodium acetate (CH3COONa), sodium bisulfite (NaHSO3), and water (H2O). The balanced chemical equation for this reaction is: 2CH3COOH + Na2SO3 → 2CH3COONa + NaHSO3 + H2O. This reaction is a double displacement reaction where the cations and anions of the reactants switch places to form the products.