yes although, technically it isn't even considered basic because there are no OH- ions...
if it read NaOH it would be a strong base because the Na+ and OH- ions dissosociate completely
so it is can be considered a weak base because it isn't a strong base.
Sodium sulfite (Na2SO3) is not a base; it is a salt that is the sodium salt of sulfurous acid. It can act as a reducing agent in some chemical reactions.
Supposed you mean an aqueous solution of Na2SO3 , you will find in it the following ions:Na+SO32-very small amount of HSO3- (from the 'weak base' reaction with water: OH- is also formed)
The balanced chemical equation for the reaction between Na2SO3 (sodium sulfite) and HCl (hydrochloric acid) is: Na2SO3 + 2HCl -> 2NaCl + H2O + SO2
Ethanol is a weak base.
The formula is Na2SO3 , because Na have 1 valence electrone and SO3 is a polyatomic with 2 valence electrons so u cross multiply Na1 * SO3(2) =Na2SO3
Sodium sulfite (Na2SO3) is not a base; it is a salt that is the sodium salt of sulfurous acid. It can act as a reducing agent in some chemical reactions.
Supposed you mean an aqueous solution of Na2SO3 , you will find in it the following ions:Na+SO32-very small amount of HSO3- (from the 'weak base' reaction with water: OH- is also formed)
The balanced chemical equation for the reaction between Na2SO3 (sodium sulfite) and HCl (hydrochloric acid) is: Na2SO3 + 2HCl -> 2NaCl + H2O + SO2
Ammonia is a weak base
Ethanol is a weak base.
A weak base is a type of base. This type of base is considered weak because when it is put in an aqueous solution, it cannot ionize.
The formula is Na2SO3 , because Na have 1 valence electrone and SO3 is a polyatomic with 2 valence electrons so u cross multiply Na1 * SO3(2) =Na2SO3
NaHCO3 is a weak base, with a conjugate acid of H2CO3+.
No, methanol is not considered a weak base. It is actually a weak acid.
HCOO- is the conjugate base of formic acid (HCOOH) which is a weak acid. Therefore, HCOO- is a weak base.
Methanol (MeOH) is a weak base.
Na2SO3(aq) + 2HCl(aq) ---> 2NaCl(aq) + SO2(g) + H2O(l)