yes
Adding a small amount of NaOH to a buffer solution will increase the pH of the solution. This is because NaOH is a strong base that will react with the weak acid in the buffer, causing the pH to rise.
Quantity matters. If there is a lot of buffer (in terms of moles) and relatively little NaOH then the buffer will prevent any change in pH. If there is relatively more NaOH than buffer, then of course the pH will rise.
No, NaOH and NaCl do not form a buffer system. A buffer system consists of a weak acid and its conjugate base, or a weak base and its conjugate acid, to help maintain a stable pH. NaOH is a strong base and NaCl is a salt, so they do not act as a buffer system together.
The net ionic equation for HF and NaOH is: HF (aq) + NaOH (aq) -> H2O (l) + NaF (aq).
It is BASIC because, if combined with water, it produces a strong base: NaOH
Adding a small amount of NaOH to a buffer solution will increase the pH of the solution. This is because NaOH is a strong base that will react with the weak acid in the buffer, causing the pH to rise.
Quantity matters. If there is a lot of buffer (in terms of moles) and relatively little NaOH then the buffer will prevent any change in pH. If there is relatively more NaOH than buffer, then of course the pH will rise.
No, NaOH and NaCl do not form a buffer system. A buffer system consists of a weak acid and its conjugate base, or a weak base and its conjugate acid, to help maintain a stable pH. NaOH is a strong base and NaCl is a salt, so they do not act as a buffer system together.
The net ionic equation for HF and NaOH is: HF (aq) + NaOH (aq) -> H2O (l) + NaF (aq).
When a strong acid is added to a buffer solution containing NaF and HF, the strong acid will react with the weak base (F-) to form HF. The buffer solution will resist changes in pH by the common ion effect, maintaining the solution's acidity around the initial pH of the buffer. The chemical equation can be written as H+ + F- ↔ HF.
It is BASIC because, if combined with water, it produces a strong base: NaOH
This reaction is:2 F2 + 4 NaOH = 4 NaF + 2 H2O + O2
No it's is HF + (OH)- --> F- + H2O sodium is a spectator ion so it isn't included on each side.
I guess it would be NaOH and CO2. This explains why it is an alkaline buffer
No, a buffer solution requires a significant amount of a weak acid and its conjugate base, or a weak base and its conjugate acid, in roughly equal amounts. The reaction between HCl and NaOH results in the formation of water and salt, not a buffer solution.
When NaOH is added to a buffer, the change in pH can be calculated using the Henderson-Hasselbalch equation. This equation is pH pKa log(A-/HA), where pKa is the acid dissociation constant of the weak acid in the buffer, A- is the concentration of the conjugate base, and HA is the concentration of the weak acid. By plugging in the initial concentrations of the weak acid and its conjugate base, as well as the amount of NaOH added, you can calculate the change in pH.
CH4 an organic alkane. (Methane) NaF An inorganic salt ( Sodium fluoride) NaOH A soluble base / alkali ( Sodium hydroxide) BaSO4 An inorganic salt ) Barium sulphate) NH3 A basic gas ( Ammonia) KBr An inorganic salt (Potassium bromide) HNO3 A mineral acid (Nitric acid) NB When writing chemical formula remember single letter elements use CAPITAL letter. Two-letter elements have first letter as a capital and the second letter as small/lower case. This is standard world wide practice in order to avoid confusion over names.