Ionic (made up of the ions Na+ and OH- )
The chemical reaction is:2 NaOH + CoCl2 = 2 NaCl + Co(OH)2
it is a ionic compound becuase it involves a metal which is what an ionic comund is
To write the net ionic equation for NaOH + H2C4H4O6, first write the balanced molecular equation: NaOH + H2C4H4O6 -> NaC4H4O6 + H2O. Then, split the compounds into ions and remove spectator ions: Na+ + OH- + H2C4H4O6 -> Na+ + C4H4O6^2- + H2O. The net ionic equation is OH- + H2C4H4O6 -> C4H4O6^2- + H2O.
The net ionic equation for HF and NaOH is: HF (aq) + NaOH (aq) -> H2O (l) + NaF (aq).
The complete ionic equation for NaOH (sodium hydroxide) dissolved in water is: Na⁺ + OH⁻ + H₂O → Na⁺(aq) + OH⁻(aq).
It can be either. For example sodium hydroxide (NaOH) is a base that is ionic while ammonia (NH3) is a base that is molecular.
The chemical reaction is:2 NaOH + CoCl2 = 2 NaCl + Co(OH)2
it is a ionic compound becuase it involves a metal which is what an ionic comund is
To write the net ionic equation for NaOH + H2C4H4O6, first write the balanced molecular equation: NaOH + H2C4H4O6 -> NaC4H4O6 + H2O. Then, split the compounds into ions and remove spectator ions: Na+ + OH- + H2C4H4O6 -> Na+ + C4H4O6^2- + H2O. The net ionic equation is OH- + H2C4H4O6 -> C4H4O6^2- + H2O.
The net ionic equation for HF and NaOH is: HF (aq) + NaOH (aq) -> H2O (l) + NaF (aq).
Ionic Molecular
PtO2 is ionic
molecular
ionic
it is ionic
It is molecular
NaOH and H2O form a solution of Na+(aq) and OH-(aq) ions (the solvent water, aq, is written as subscripted (aq) ) To make 1 Normal solution you need to know the equivalent of NaOH, which is calculated by dividing Molecular weight by 1, that is 40 divided by 1= 40. So the equivalent weight of NaOH is 40. To make 1 N solution, dissolve 40.00 g of sodium hydroxide in water to make volume of 1 liter.