Yes
Yes, 1-pentanol is soluble in NaOH because it can form hydrogen bonds with the hydroxide ions in NaOH, allowing it to dissolve.
The balanced equation for Na2O + H2O → 2 NaOH is: Na2O + H2O → 2 NaOH
KHC8H4O4(aq) + NaOH(aq) → KNaC8H4O4(aq) + H2O(l) NaOH(aq) + KHP(aq) => Na+ + KP- + H2O(l)
Yes, benzoic acid is soluble in NaOH because when it reacts with NaOH, it forms the water-soluble salt sodium benzoate.
Yes, lactose soluble is NaOH. Sodium is Na always and is water soluble. The website Study Mode has many examples of experiments done to prove that lactose is soluble.
Yes, 1-pentanol is soluble in NaOH because it can form hydrogen bonds with the hydroxide ions in NaOH, allowing it to dissolve.
The balanced equation for Na2O + H2O → 2 NaOH is: Na2O + H2O → 2 NaOH
KHC8H4O4(aq) + NaOH(aq) → KNaC8H4O4(aq) + H2O(l) NaOH(aq) + KHP(aq) => Na+ + KP- + H2O(l)
Yes, benzoic acid is soluble in NaOH because when it reacts with NaOH, it forms the water-soluble salt sodium benzoate.
HNO3+ NaOH = NaNO3+ H2O is a neutralization reaction
Yes, lactose soluble is NaOH. Sodium is Na always and is water soluble. The website Study Mode has many examples of experiments done to prove that lactose is soluble.
2 Na + 2 H2O = 2 NaOH + H22 NaOH + Ca(NO3)2 = 2 NaNO3 + Ca(OH)2Calcium hydroxide is not soluble in water.
Thymol is soluble in NaOH because it can form a salt with the hydroxide ion (OH-) in NaOH through ion-dipole interactions. This interaction allows thymol to dissociate into ions and become soluble in the aqueous NaOH solution.
Methoxyphenol is a phenol derivative and so, is soluble in water. This means that methoxyphenol will dissolve in an aqueous NaOH solution, but will not react with the NaOH.
HCl + NaOH --> NaCl + H2O is balanced as you wrote it.But, since sodium is always soluble in water at temperatures below the boiling point of the solution, the net ionic equation for the reaction at temperatures lower than the boiling point would actually be: HCl + OH- --> Cl- + H2OOr, if the hydrochloric acid was already in solution, then simplyH+ + OH- ---> H2O
NaOH(hydroxide) + HCl(acid) ---------> NaCl(salt) + H2O(water)
The reaction between NaOH and HCl produces NaCl (sodium chloride) and H2O (water). The balanced chemical equation is: NaOH + HCl → NaCl + H2O.