Yes, RbNO3 is an ionic compound. It consists of a rubidium cation (Rb+) and a nitrate anion (NO3-), which are held together by strong ionic bonds due to the transfer of electrons from rubidium to nitrate.
The chemical equation for rubidium nitrate is RbNO3.
RbOH + HNO ==> H2O + RbNO. NOTE: HNO (nitroxyl) is normally found in the gas phase. In aqueous soln., it can act as an acid to produce H+ + NO-. If the question was mean to read RbOH + HNO3, the the products would be H2O + RbNO3.
Rubidium Nitrate
The chemical formula for rubidium nitrate is RbNO3. It consists of one rubidium ion (Rb+) and one nitrate ion (NO3-).
The reaction of rubidium hydroxide (RbOH) with nitric acid (HNO3) would produce rubidium nitrate (RbNO3) and water (H2O).
The chemical equation for rubidium nitrate is RbNO3.
5 moles RbNO3 (3 moles O2/2 moles RbNO3) = 7.5 moles oxygen gas produced
RbOH + HNO ==> H2O + RbNO. NOTE: HNO (nitroxyl) is normally found in the gas phase. In aqueous soln., it can act as an acid to produce H+ + NO-. If the question was mean to read RbOH + HNO3, the the products would be H2O + RbNO3.
The decomposition of rubidium nitrate (RbNO3) can be represented by the balanced chemical equation: [ 2 \text{RbNO}_3(s) \rightarrow 2 \text{Rb}(s) + 2 \text{NO}_2(g) + \text{O}_2(g) ] From this equation, we see that 2 moles of RbNO3 produce 1 mole of O2. Therefore, from 5.0 moles of RbNO3, the amount of O2 produced can be calculated as follows: [ \text{Moles of O2} = \frac{5.0 , \text{mol RbNO3}}{2} = 2.5 , \text{mol O2} ] Thus, 2.5 moles of O2 are produced from 5.0 moles of RbNO3.
Rubidium Nitrate
These are the ions and their charges: Rb+1 N-3The charges have to add up to zero, so two +1 Rb ions were added to cancel out the -3 charge of N: Rb+1 Rb+1 Rb+1 N-3Simplify: Rb3N
Two: the rubidium ion Rb+ and the nitrate ion NO3-
The chemical formula for rubidium nitrate is RbNO3. It consists of one rubidium ion (Rb+) and one nitrate ion (NO3-).
The reaction of rubidium hydroxide (RbOH) with nitric acid (HNO3) would produce rubidium nitrate (RbNO3) and water (H2O).
RbI + AgNO3 ---> RbNO3 + AgI It is displacement reaction. Rubidium is an alkali metal hence it is highly reactive and easily displaces silver from silver nitrate solution.
PtO2 is ionic
Potassium iodide is ionic.