RbI + AgNO3 ---> RbNO3 + AgI
It is displacement reaction. Rubidium is an alkali metal hence it is highly reactive and easily displaces silver from silver nitrate solution.
When calcium nitrate (Ca(NO₃)₂) reacts with potassium iodide (KI), the balanced chemical equation is: [ \text{Ca(NO}_3\text{)}_2 + 2 \text{KI} \rightarrow \text{CaI}_2 + 2 \text{KNO}_3 ] In this reaction, one mole of calcium nitrate reacts with two moles of potassium iodide to produce one mole of calcium iodide and two moles of potassium nitrate.
The chemical equation for Strontium Iodide is SrI2, which represents the compound formed by the elements strontium (Sr) and iodine (I) combining in a 1:2 ratio.
When silver nitrate and strontium iodide react, a double displacement reaction occurs. Silver iodide and strontium nitrate are formed as products. Silver iodide is a yellow precipitate while strontium nitrate remains in solution.
HgI is not a chemical reaction, it is the empirical formula for the compound Mercury (I) iodide, Hg2I2
The molecular formula for silver iodide is AgI.Silver iodide is an inorganic, yellow compound which is used in many things, from silver-based photography to antiseptic.
The chemical equation is: Na+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + Na+[NO3]- (aq)
The chemical name of the compound RbI is rubidium iodide.
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
The chemical formula of rubidium chloride is RbCl.
lead nitrate(Pb(NO3)2 + potassium iodide(KI) = lead iodide(PbI) + potassium nitrate (KNO3)
Equation: Pb(NO3)2 + KI ----> PbI2 + KNO3
The balanced chemical equation for silver nitrate (AgNO3) plus calcium iodide (CaI2) is: 2AgNO3 + CaI2 -> 2AgI + Ca(NO3)2
The chemical equation for the reaction between lead nitrate (Pb(NO3)2) and potassium iodide (KI) to form lead iodide (PbI2) and potassium nitrate (KNO3) is: Pb(NO3)2 + 2KI → 2KNO3 + PbI2
When silver nitrate reacts with potassium iodide, a precipitation reaction occurs where silver iodide is formed. The balanced chemical equation for this reaction is: AgNO3 + KI -> AgI + KNO3. The silver iodide formed will appear as a yellow solid precipitate.
When iodide is mixed with silver nitrate, a yellow precipitate of silver iodide is formed due to a double displacement reaction. This reaction can be represented by the chemical equation: 2AgNO3 + 2KI → 2AgI + 2KNO3.
Rubidium metal would react with iodine to make rubidium iodide , according to the equation: 2 Ru + I2 -> 2 RuI