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, I'm currently studying Chemistry at University and I think I can help you.
SnI4 is a nonpolar compound. It is nonpolar because of the tetrahedric structure (similar to CCl4). As such, its soluble in nonpolar solvents such as hexane. Its a little soluble in dichloromethane, since its polarity is only moderate. Its not soluble at all in water. To be more specific, it actually hydrolises completely and readily if water is present, even in the air, and forms SnO2 which is also insoluble in water.
During the synthesis of this compound, extreme care is taken so that there is no contact of the product with water.
Dichloromethane, due to the slight solubility, can be used as a solvent for recrystalization of the compound, for its solubility increases with an increment in temperature.
So the answer is: its soluble in hexane, moderately in dichloromethane, and not at all in water (even hydrolyses readily).
Hope that helps,
Alonso
What else can I help you with?
Why is SnI4 soluble in chloroform?
SnI4 is soluble in chloroform because chloroform is a nonpolar solvent, while SnI4 has a nonpolar nature due to the presence of polarizable iodine atoms. This nonpolar-polar interaction allows for the dissolution of SnI4 in chloroform.
What is the name for the ionic compound SnI4?
This would be referred to as Tin Tetraiodide.
Name the following compounds SnI4 N2O3 PCl3 and CSe2?
SNI4=Stannic Iodide/TIn (VI) Iodide N203=Nitrogen tri oxide PCl3=Phosphorus tri chloride CSe2=Carbon deselenide
What is the chemical formula for the compound formed between tin(IV) and iodine?
Tin has two oxidation states (II and IV), and exhibits approximately equal stability in both its II and IV oxidation state. The chemical formula Tin (II) Iodide is SnI2. The chemical formula for Tin (IV) Iodide is SnI4.
What is Tetraiodobis triphenylphosphine tin iv?
Tetraiodobis(triphenylphosphine)tin(IV) is a chemical compound with the formula [SnI4(PPh3)2]. It is a coordination complex consisting of a tin(IV) center coordinated to two triphenylphosphine ligands and four iodine atoms. This compound has been studied for its potential applications in materials chemistry and catalysis.
Why is SnI4 soluble in chloroform?
SnI4 is soluble in chloroform because chloroform is a nonpolar solvent, while SnI4 has a nonpolar nature due to the presence of polarizable iodine atoms. This nonpolar-polar interaction allows for the dissolution of SnI4 in chloroform.
What happens when water is added to a metal halide namely SnI4?
When water is added to a metal namely SnI4, nothing will happen. Both water and metal will remain at its normal state.
Is SnI4 soluble in KI solution?
Hi, having a solution of KI implies having H20 so tin iodide will hydrolyze forming the tin oxide and HI. Another interesting reaction is when you add KI (in solid phase) into tin iodide solution (dissolved in acetone). You will obtain a salt like this: K(SnI5) I hope I helped you. Note that this answer could be wrong, I'm currently a student of chemistry and I have a lot to learn yet.
What is the name for the ionic compound SnI4?
This would be referred to as Tin Tetraiodide.
Name the following compounds SnI4 N2O3 PCl3 and CSe2?
SNI4=Stannic Iodide/TIn (VI) Iodide N203=Nitrogen tri oxide PCl3=Phosphorus tri chloride CSe2=Carbon deselenide
What is the chemical formula for the compound formed between tin(IV) and iodine?
Tin has two oxidation states (II and IV), and exhibits approximately equal stability in both its II and IV oxidation state. The chemical formula Tin (II) Iodide is SnI2. The chemical formula for Tin (IV) Iodide is SnI4.
What compound is Snl4?
Tin(IV) iodide is represented by the chemical formula SnI4.
What is the formula for Tin(IV) iodide?
Tin has two oxidation states (II and IV), and exhibits approximately equal stability in both its II and IV oxidation state. The chemical formula Tin (II) Iodide is SnI2. The chemical formula for Tin (IV) Iodide is SnI4.
What is Tetraiodobis triphenylphosphine tin iv?
Tetraiodobis(triphenylphosphine)tin(IV) is a chemical compound with the formula [SnI4(PPh3)2]. It is a coordination complex consisting of a tin(IV) center coordinated to two triphenylphosphine ligands and four iodine atoms. This compound has been studied for its potential applications in materials chemistry and catalysis.
How can stannous iodide be converted to stannic iodide?
Stannous iodide can be converted to stannic iodide by reacting it with an oxidizing agent, such as hydrogen peroxide. The stannous iodide is oxidized to form stannic iodide in the reaction. The chemical equation for this reaction is: 2 SnI2 + H2O2 → 2 SnI4 + 2 H2O.
What is the balanced equation when tin iv iodide is mixed with acetone?
The chemical formula of tin IV acetate is Sn(C2H3O2)4.
