, I'm currently studying Chemistry at University and I think I can help you.
SnI4 is a nonpolar compound. It is nonpolar because of the tetrahedric structure (similar to CCl4). As such, its soluble in nonpolar solvents such as hexane. Its a little soluble in dichloromethane, since its polarity is only moderate. Its not soluble at all in water. To be more specific, it actually hydrolises completely and readily if water is present, even in the air, and forms SnO2 which is also insoluble in water.
During the synthesis of this compound, extreme care is taken so that there is no contact of the product with water.
Dichloromethane, due to the slight solubility, can be used as a solvent for recrystalization of the compound, for its solubility increases with an increment in temperature.
So the answer is: its soluble in hexane, moderately in dichloromethane, and not at all in water (even hydrolyses readily).
Hope that helps,
Alonso
SNI4=Stannic Iodide/TIn (VI) Iodide N203=Nitrogen tri oxide PCl3=Phosphorus tri chloride CSe2=Carbon deselenide
Tin has two oxidation states (II and IV), and exhibits approximately equal stability in both its II and IV oxidation state. The chemical formula Tin (II) Iodide is SnI2. The chemical formula for Tin (IV) Iodide is SnI4.
[SnI4(PPh3)2] is a tin complex that forms brownish-red crystals.
This would be referred to as Tin Tetraiodide.
When water is added to a metal namely SnI4, nothing will happen. Both water and metal will remain at its normal state.
SNI4=Stannic Iodide/TIn (VI) Iodide N203=Nitrogen tri oxide PCl3=Phosphorus tri chloride CSe2=Carbon deselenide
Tin has two oxidation states (II and IV), and exhibits approximately equal stability in both its II and IV oxidation state. The chemical formula Tin (II) Iodide is SnI2. The chemical formula for Tin (IV) Iodide is SnI4.
[SnI4(PPh3)2] is a tin complex that forms brownish-red crystals.
This would be referred to as Tin Tetraiodide.
By the use of an oxidizing agent such as a mixture of Oxygen and Water6 SnI2 + O2 + 2 H2O ----> 2 SnI4 + 4 Sn(OH)I
Hi, having a solution of KI implies having H20 so tin iodide will hydrolyze forming the tin oxide and HI. Another interesting reaction is when you add KI (in solid phase) into tin iodide solution (dissolved in acetone). You will obtain a salt like this: K(SnI5) I hope I helped you. Note that this answer could be wrong, I'm currently a student of chemistry and I have a lot to learn yet.
Tin has two oxidation states (II and IV), and exhibits approximately equal stability in both its II and IV oxidation state. The chemical formula Tin (II) Iodide is SnI2. The chemical formula for Tin (IV) Iodide is SnI4.