Tin (IV) selenide, SnSe2, is a covalent compound. It is composed of nonmetal elements, tin (Sn) and selenium (Se), which typically form covalent bonds by sharing electrons to achieve stability.
The systematic name of this ionic compound is Tin(IV) Selenide.
Tin(IV) selenide
Tin(IV) oxide is primarily considered an ionic compound, as it is composed of a metal cation (tin) and a non-metal anion (oxygen) that form an ionic bond.
Tin(IV) has a positive four charge. Selenide usually forms a 2- ion. Ionic compounds need a neutral, balanced charge. With the above information, the rest is pretty much just math. Tin - Sn(+4) Selenide - Se(-2) So you need two of Se to balance the +4 with a -4. = SnSe2 The answer above is OK, however if you are familiar with the idea of oxidation states SnIV is tin in its 4th oxidation state. Selenium has a common oxidation stae of -2 and once again you can do the math. The bonding in SnSe2 is not ionic so using oxidation states is preferable.
Tin IV iodide has a covalent bond between the tin atom and the iodine atoms, where the tin atom shares its electrons with the iodine atoms to form a stable structure. This compound also exhibits ionic character due to the significant electronegativity difference between tin and iodine atoms.
The systematic name of this ionic compound is Tin(IV) Selenide.
Tin(IV) selenide
Tin(IV) oxide is primarily considered an ionic compound, as it is composed of a metal cation (tin) and a non-metal anion (oxygen) that form an ionic bond.
Tin(IV) has a positive four charge. Selenide usually forms a 2- ion. Ionic compounds need a neutral, balanced charge. With the above information, the rest is pretty much just math. Tin - Sn(+4) Selenide - Se(-2) So you need two of Se to balance the +4 with a -4. = SnSe2 The answer above is OK, however if you are familiar with the idea of oxidation states SnIV is tin in its 4th oxidation state. Selenium has a common oxidation stae of -2 and once again you can do the math. The bonding in SnSe2 is not ionic so using oxidation states is preferable.
Tin IV iodide has a covalent bond between the tin atom and the iodine atoms, where the tin atom shares its electrons with the iodine atoms to form a stable structure. This compound also exhibits ionic character due to the significant electronegativity difference between tin and iodine atoms.
This would be referred to as Tin Tetraiodide.
lead (IV) selenide
Cesium selenide
Tin (IV) oxide is an ionic compound. It consists of tin cations (Sn^4+) and oxide anions (O^2-), which form a lattice structure through ionic bonds.
Tin has two oxidation states (II and IV), and exhibits approximately equal stability in both its II and IV oxidation state. The chemical formula Tin (II) Iodide is SnI2. The chemical formula for Tin (IV) Iodide is SnI4.
The name for Sn2S4 is tin(IV) sulfide or stannic sulfide.
The ionic compound SnBr4 is called tin (IV) bromide. It consists of tin cations with a +4 charge and bromide anions with a -1 charge.