Judging by the difference in Electronegativities its likely covalent.
Tin has two oxidation states (II and IV), and exhibits approximately equal stability in both its II and IV oxidation state. The chemical formula Tin (II) Iodide is SnI2. The chemical formula for Tin (IV) Iodide is SnI4.
This would be referred to as Tin Tetraiodide.
Lead (II) iodide Transition metals always need roman numerals to represent their charges.
tin hydroxide would be formed if water was present during the experiment which would make it impossile to make the desired product.
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Sn4+ is the symbol for Tin(IV), that is, the element tin with a oxidation state of 4.
Tin has two oxidation states (II and IV), and exhibits approximately equal stability in both its II and IV oxidation state. The chemical formula Tin (II) Iodide is SnI2. The chemical formula for Tin (IV) Iodide is SnI4.
Tin (IV) Iodide
Tin has two oxidation states (II and IV), and exhibits approximately equal stability in both its II and IV oxidation state. The chemical formula Tin (II) Iodide is SnI2. The chemical formula for Tin (IV) Iodide is SnI4.
This would be referred to as Tin Tetraiodide.
The chemical formula of tin IV acetate is Sn(C2H3O2)4.
Lead (II) iodide is PbI2. Lead (IV) iodide is PbI4.
Lead (II) iodide Transition metals always need roman numerals to represent their charges.
Potassium iodide (KI) has an ionic bond.
The chemical name for PtI4 is platinum(IV) iodide.
The Answer To Your Question Is.... tin (IV) oxide
tin hydroxide would be formed if water was present during the experiment which would make it impossile to make the desired product.