Freezing point depression is a colligative property. It doesn't depend on what the solute species is, just how much of it there is. (It does matter if the solute breaks apart upon dissolving, because each part counts individually).
With that in mind, the question is nonsense.
The relationship between freezing point depression and molar mass is that the freezing point depression is directly proportional to the molar mass of the solute. This means that as the molar mass of the solute increases, the freezing point depression also increases.
The relationship between the molar mass and freezing point depression of a substance is that the freezing point depression is directly proportional to the molar mass of the solute. This means that as the molar mass of the solute increases, the freezing point depression also increases.
The freezing point depression method can be used to calculate the molar mass of a solute in a solution by measuring the decrease in the freezing point of the solvent when the solute is added. By knowing the freezing point depression constant of the solvent and the amount of solute added, the molar mass of the solute can be calculated using the formula: molar mass (freezing point depression constant molality) / freezing point depression.
The depression of the freezing point is dependent on the concentration of solute particles in a solution. More solute particles lead to a greater depression of the freezing point.
The relationship between molar mass and freezing point depression in lab answers is that the freezing point depression is directly proportional to the molar mass of the solute. This means that as the molar mass of the solute increases, the freezing point depression also increases.
The depression of the freezing point is dependent on the nature of solvent and concentration of solute.
The relationship between freezing point depression and molar mass is that the freezing point depression is directly proportional to the molar mass of the solute. This means that as the molar mass of the solute increases, the freezing point depression also increases.
The relationship between the molar mass and freezing point depression of a substance is that the freezing point depression is directly proportional to the molar mass of the solute. This means that as the molar mass of the solute increases, the freezing point depression also increases.
The freezing point depression method can be used to calculate the molar mass of a solute in a solution by measuring the decrease in the freezing point of the solvent when the solute is added. By knowing the freezing point depression constant of the solvent and the amount of solute added, the molar mass of the solute can be calculated using the formula: molar mass (freezing point depression constant molality) / freezing point depression.
The depression of the freezing point is dependent on the concentration of solute particles in a solution. More solute particles lead to a greater depression of the freezing point.
The relationship between molar mass and freezing point depression in lab answers is that the freezing point depression is directly proportional to the molar mass of the solute. This means that as the molar mass of the solute increases, the freezing point depression also increases.
The freezing point depression constant for Naphthalene is 6.9 degrees Celsius/mhttp://en.wikipedia.org/wiki/Freezing-point_depression
The answer is "Freezing point depression" on Apex
The freezing point depression constant for water is 1.86 degrees Celsius per molal.
To calculate freezing point depression in a solution, you can use the formula: Tf i Kf m. Tf represents the freezing point depression, i is the van't Hoff factor, Kf is the cryoscopic constant, and m is the molality of the solution. By plugging in these values, you can determine the freezing point depression of the solution.
Since benzene is the solute and chloroform is the solvent, this is a non-electrolyte solution. The freezing point depression equation is ΔTf = Kf * m, where ΔTf is the freezing point depression, Kf is the freezing point depression constant for chloroform, and m is the molality of the solution. From this, you can calculate the freezing point of the solution.
To determine the freezing point of the solution, you need to calculate the molality of the NiSO4 in the H2O solution. Once you have the molality, you can then use the formula for freezing point depression to find the freezing point. This formula is ΔTf = Kf * m, where ΔTf is the freezing point depression, Kf is the freezing point depression constant (for water it is 1.86 °C kg/mol), and m is the molality of the solution. Finally, add the freezing point depression to the normal freezing point of water (0°C) to find the freezing point of the solution.