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What is the freezing point depression constant for water and how does it affect the freezing point of water?
The freezing point depression constant for water is 1.86 degrees Celsius per molal. This means that for every mole of solute added to water, the freezing point of water decreases by 1.86 degrees Celsius. The presence of solute particles disrupts the formation of ice crystals, lowering the freezing point of the solution compared to pure water.
What would the final freezing point of water be if 3mol of NaCl were added to 1kg of water?
The freezing point depression constant for water is 1.86°C kg/mol. First, calculate the molality of the solution: 3 mol NaCl / 1 kg H2O = 3 mol/kg. Next, calculate the freezing point depression: ΔTf = iKfm where i is the van't Hoff factor (2 for NaCl), Kf is the freezing point depression constant, and m is the molality. Plugging in the values, the final freezing point would be -11.16°C.
How much would the freezing point decrease if a 3.23 molal solution were achieved?
The freezing point depression of a solution is given by the equation ΔTf = Kf * m, where ΔTf is the freezing point depression, Kf is the cryoscopic constant, and m is the molality of the solution. With the molality (m) of 3.23 molal and the cryoscopic constant for water (Kf) being approximately 1.86 ºC kg/mol, you can calculate the freezing point depression.
21.6 g NiSO4 in 1.00 102g Hu2082O what is the freezing point of this solution?
To determine the freezing point of the solution, you need to calculate the molality of the NiSO4 in the H2O solution. Once you have the molality, you can then use the formula for freezing point depression to find the freezing point. This formula is ΔTf = Kf * m, where ΔTf is the freezing point depression, Kf is the freezing point depression constant (for water it is 1.86 °C kg/mol), and m is the molality of the solution. Finally, add the freezing point depression to the normal freezing point of water (0°C) to find the freezing point of the solution.
What is the freezing point of a solution that contains 0.550 moles of NaI in 615 g of water?
To calculate the freezing point depression, you first need to find the molality of the solution using the moles of solute and mass of solvent. Then, use the molality to find the freezing point depression constant of water. Finally, apply the formula ΔTf = Kf * molality to find the freezing point depression.
What is the freezing point depression constant for water and how does it affect the freezing point of water?
The freezing point depression constant for water is 1.86 degrees Celsius per molal. This means that for every mole of solute added to water, the freezing point of water decreases by 1.86 degrees Celsius. The presence of solute particles disrupts the formation of ice crystals, lowering the freezing point of the solution compared to pure water.
What would the final freezing point of water be if 3 mol of sugar were added to 1 kg of water?
-5.58 C
What would the final freezing point of water be if 3mol of NaCl were added to 1kg of water?
The freezing point depression constant for water is 1.86°C kg/mol. First, calculate the molality of the solution: 3 mol NaCl / 1 kg H2O = 3 mol/kg. Next, calculate the freezing point depression: ΔTf = iKfm where i is the van't Hoff factor (2 for NaCl), Kf is the freezing point depression constant, and m is the molality. Plugging in the values, the final freezing point would be -11.16°C.
How much would the freezing point decrease if a 3.23 molal solution were achieved?
The freezing point depression of a solution is given by the equation ΔTf = Kf * m, where ΔTf is the freezing point depression, Kf is the cryoscopic constant, and m is the molality of the solution. With the molality (m) of 3.23 molal and the cryoscopic constant for water (Kf) being approximately 1.86 ºC kg/mol, you can calculate the freezing point depression.
21.6 g NiSO4 in 1.00 102g Hu2082O what is the freezing point of this solution?
To determine the freezing point of the solution, you need to calculate the molality of the NiSO4 in the H2O solution. Once you have the molality, you can then use the formula for freezing point depression to find the freezing point. This formula is ΔTf = Kf * m, where ΔTf is the freezing point depression, Kf is the freezing point depression constant (for water it is 1.86 °C kg/mol), and m is the molality of the solution. Finally, add the freezing point depression to the normal freezing point of water (0°C) to find the freezing point of the solution.
What is the freezing point of a solution that contains 0.550 moles of NaI in 615 g of water?
To calculate the freezing point depression, you first need to find the molality of the solution using the moles of solute and mass of solvent. Then, use the molality to find the freezing point depression constant of water. Finally, apply the formula ΔTf = Kf * molality to find the freezing point depression.
What would the final freezing point of water be if 3 mol of sugar were added to kg of water (Kf 1.86?
The freezing point depression can be calculated using the formula ΔTf = Kf * m, where Kf is the freezing point depression constant (1.86 °C/kg) and m is the molality of the solution. With 3 mol of sugar dissolved in 1 kg of water, the molality is 3 mol / 1 kg = 3 mol/kg. Thus, the freezing point depression would be ΔTf = 1.86 °C/kg * 3 mol/kg = 5.58 °C. The final freezing point of the solution would be the freezing point of water (0°C) minus the freezing point depression, so the final freezing point would be -5.58°C.
The solution has a freezing point of -2.79 . The freezing point depression constant for water is 1.86 K m-1. What is the nitrate concentration in the solution?
To find the nitrate concentration in the solution, you can use the formula: ΔTf = Kf * m, where ΔTf is the freezing point depression (-2.79°C), Kf is the freezing point depression constant (1.86 K m^-1), and m is the molality of the solution. Calculate the molality of the solution and then convert it to nitrate concentration using the molecular weight of the nitrate ion.
What would be the final freezing point of water be if 3 mol of sugar were added to 1 kg of water?
-5.58 C
What would the final freezing point of water be if 3 mole of sugar were added to 1 kg of water?
The CHANGE in freezing point can be determined from ∆T = imK where ∆T is the change in freezing point, i is van't Hoff factor (1 for sugar, a non electrolyte), m is molality (moles solute/kg solvent), and K is the freezing point constant for water (1.86). Thus ∆T = (1)(3)(1.86) = 5.58ºC. So, the FINAL freezing point will be -5.58ºC
What is the freezing point of a solution made by dissolving 352 g of ethylene glycol in 648 g of water?
The freezing point of the solution can be calculated using the formula: ΔTf = Kf * m. First, calculate the molality (m) of the solution by dividing the moles of solute by the mass of the solvent in kg. Then, use the molality and the freezing point depression constant (Kf) for water (1.86 °C/m) to find the freezing point depression (ΔTf). Finally, subtract ΔTf from the normal freezing point of water (0°C) to find the freezing point of the solution.
What is the change of the freezing point of water when 35.5 g sucrose is dissolved in 55 g of water?
The change in freezing point of water can be calculated using the formula: ΔTf = Kf * m, where Kf is the freezing point depression constant (1.86 °C kg/mol for water) and m is the molality of the solution. From the given masses, you can calculate the molality of the solution and then use it to find the change in freezing point.
