-5.58 C
-5.58 C
The normal freezing temperature for pure water is 0c. Howeverif sugar is added in the pure water, the freezing point will be lower than zero. How far below zero will depend on the sugar concentration in the water.
7.44 C
The freezing point depression constant for water is approximately 1.858°C kg/mol. Using the formula ∆Tf = iKfm, where i is the van't Hoff factor, Kf is the freezing point depression constant, and m is the molality, we can calculate the change in freezing point. In this case, with 4 mol of sugar added to 1 kg of water (1000 g), the molality is 4 mol / 1000 g = 4 m/kg. Plugging these values in, we get ∆Tf = 1 * 1.858 * 4 = 7.432°C. The freezing point of water would decrease by 7.432°C.
Sugar and salt dissolved in water lower the freezing point of water. This occurs because the solute particles disrupt the formation of ice crystals, making it harder for water molecules to align into a solid structure. As a result, the solution needs to be cooled to a lower temperature before it can freeze.
-5.58 C
The CHANGE in freezing point can be determined from ∆T = imK where ∆T is the change in freezing point, i is van't Hoff factor (1 for sugar, a non electrolyte), m is molality (moles solute/kg solvent), and K is the freezing point constant for water (1.86). Thus ∆T = (1)(3)(1.86) = 5.58ºC. So, the FINAL freezing point will be -5.58ºC
The freezing point depression can be calculated using the formula ΔTf = Kf * m, where Kf is the freezing point depression constant (1.86 °C/kg) and m is the molality of the solution. With 3 mol of sugar dissolved in 1 kg of water, the molality is 3 mol / 1 kg = 3 mol/kg. Thus, the freezing point depression would be ΔTf = 1.86 °C/kg * 3 mol/kg = 5.58 °C. The final freezing point of the solution would be the freezing point of water (0°C) minus the freezing point depression, so the final freezing point would be -5.58°C.
The freezing point of water decreases by about 1.86 degrees Celsius for each mole of solute (such as sugar) dissolved in 1 kg of water. So, the freezing point would decrease by 1.86 degrees Celsius for every mole of sugar added.
The normal freezing temperature for pure water is 0c. Howeverif sugar is added in the pure water, the freezing point will be lower than zero. How far below zero will depend on the sugar concentration in the water.
The normal freezing temperature for pure water is 0c. Howeverif sugar is added in the pure water, the freezing point will be lower than zero. How far below zero will depend on the sugar concentration in the water.
-5.58 C
Salt and sugar can both help ice melt faster by lowering the freezing point of water. Vinegar, on the other hand, can lower the freezing point even more than salt or sugar, potentially making ice freeze longer when added to water.
Yes, sugar can lower the freezing point of water. When sugar is dissolved in water, it disrupts the water molecules' ability to form a crystal structure, which results in the freezing point of the solution being lower than that of pure water.
7.44 degrees c.
The freezing point depression formula is ΔT = i * Kf * m, where i is the van't Hoff factor, Kf is the cryoscopic constant (1.86°C kg/mol for water), and m is the molality of the solution. The van't Hoff factor for sugar is 1, so the molality of the solution is 3 mol / 1 kg = 3 mol/kg. Therefore, ΔT = 1 * 1.86 * 3 = 5.58°C. The final freezing point of water would be 0°C - 5.58°C = -5.58°C.
Adding 4 mol sugar to 1 g (gram) water is impossible !