Yes, it is
The filtrate of lead nitrate and sodium iodide would contain soluble sodium nitrate and insoluble lead iodide. Lead iodide is a yellow solid that precipitates out of the solution, while sodium nitrate remains in the filtrate as it is soluble in water.
The ionic compound of sodium iodide is NaI. It is composed of sodium (Na+) ions and iodide (I-) ions held together by ionic bonds.
You can separate a mixture of iodine solid and sodium iodide by using the difference in solubility of the two compounds. Since sodium iodide is soluble in water while iodine is not, you can dissolve the mixture in water to dissolve the sodium iodide, leaving the solid iodine behind. The two can then be separated by filtration.
The IUPAC name for sodium iodide is sodium iodide.
Yes, three salts of group 1 elements (Lithium, Sodium Potassium and salts) are soluble in water.
It is false; sodium iodide is more soluble than sodium chloride in water.
The filtrate of lead nitrate and sodium iodide would contain soluble sodium nitrate and insoluble lead iodide. Lead iodide is a yellow solid that precipitates out of the solution, while sodium nitrate remains in the filtrate as it is soluble in water.
Sodium iodide is soluble in water.
Yes. Simple alkali metal salts tend to be soluble with extremely few exceptions; most halides are likewise soluble. An alkali metal halide, such as sodium iodide, should be expected to be extremely soluble in water.
Sodium iodide is highly soluble in water, with a solubility of approximately 184 grams per 100 mL of water at room temperature. This high solubility is due to the strong ionic interactions between the sodium cation and the iodide anion with water molecules.
This is a precipitation reaction. Halides of silver are insoluble in water (except silver fluoride) whereas all nitrates are soluble in water. Sodium salts are soluble. Thus, silver iodide is the precipitate. Formula: AgNO3(aq) + NaI(aq) -> AgI(s) + NaNO3(aq)
The ionic compound of sodium iodide is NaI. It is composed of sodium (Na+) ions and iodide (I-) ions held together by ionic bonds.
You can separate a mixture of iodine solid and sodium iodide by using the difference in solubility of the two compounds. Since sodium iodide is soluble in water while iodine is not, you can dissolve the mixture in water to dissolve the sodium iodide, leaving the solid iodine behind. The two can then be separated by filtration.
The IUPAC name for sodium iodide is sodium iodide.
Yes, three salts of group 1 elements (Lithium, Sodium Potassium and salts) are soluble in water.
They are not soluble, therefore they do not precipitate or form a color....a.k.a....no reaction...
I assume that you really mean sodium iodide (NaI), as there is no compound called sodium iodine. NaI is a white crystalline solid.