Sodium iodide is very soluble
solubility product of NaI2 is 184
Very good, like all sodium salts. 178.8 g/100 mL (20 °C) 184 g/100 mL (25 °C) 294 g/100 mL (70 °C)
Yes, to an extent of about one-fifth of the (high) solubility of lithium iodide in water.
One of the aqueous ions formed when solid sodium iodide dissolves in water is iodide (I⁻).
The solubility of sodium nitrate in benzene is likely extremely low. I know that its solubility in dry acetonitrile (<40 ug/mL H2O) is less than 1 mg/mL. So I would guess it would be even worse in a non-polar solvent like benzene.
Copper iodide (CuI2) has very low solubility in water. It is considered insoluble in water.
Yes it is Aqueous !! You need to look up the solubility table to see for yourself !! Have fun !!
You can separate a mixture of iodine solid and sodium iodide by using the difference in solubility of the two compounds. Since sodium iodide is soluble in water while iodine is not, you can dissolve the mixture in water to dissolve the sodium iodide, leaving the solid iodine behind. The two can then be separated by filtration.
Very good, like all sodium salts. 178.8 g/100 mL (20 °C) 184 g/100 mL (25 °C) 294 g/100 mL (70 °C)
It is false; sodium iodide is more soluble than sodium chloride in water.
Yes, to an extent of about one-fifth of the (high) solubility of lithium iodide in water.
When sodium iodide dissolves in water, it dissociates into sodium ions (Na+) and iodide ions (I-). These ions are surrounded by water molecules in a process called hydration. The resulting solution will conduct electricity due to the presence of these ions.
The solubility of iodide ions (I-) in water at 30 degrees Celsius is generally around 140 grams per 100 grams of water, depending on the specific iodide salt being considered (e.g., potassium iodide). This indicates that a significant amount of iodide can be dissolved in water at this temperature. However, for precise values, refer to solubility tables specific to the iodide compound of interest.
The ionic compound of sodium iodide is NaI. It is composed of sodium (Na+) ions and iodide (I-) ions held together by ionic bonds.
One of the aqueous ions formed when solid sodium iodide dissolves in water is iodide (I⁻).
The IUPAC name for sodium iodide is sodium iodide.
The solubility of potassium iodide at 30 degrees Celsius is approximately 50 grams per 100 milliliters of water.
The solubility of sodium nitrate in benzene is likely extremely low. I know that its solubility in dry acetonitrile (<40 ug/mL H2O) is less than 1 mg/mL. So I would guess it would be even worse in a non-polar solvent like benzene.