The solubility of sodium nitrate in benzene is likely extremely low. I know that its solubility in dry acetonitrile (<40 ug/mL H2O) is less than 1 mg/mL. So I would guess it would be even worse in a non-polar solvent like benzene.
Sodium iodide is highly soluble in water, with a solubility of approximately 184 grams per 100 mL of water at room temperature. This high solubility is due to the strong ionic interactions between the sodium cation and the iodide anion with water molecules.
This is a precipitation reaction. Halides of silver are insoluble in water (except silver fluoride) whereas all nitrates are soluble in water. Sodium salts are soluble. Thus, silver iodide is the precipitate. Formula: AgNO3(aq) + NaI(aq) -> AgI(s) + NaNO3(aq)
They are not soluble, therefore they do not precipitate or form a color....a.k.a....no reaction...
Sodium iodide
RAM Na=23g RMM NaI=150g Percent composition=23/150*100% =15.3
Sodium chloride is not soluble in benzene.
It is false; sodium iodide is more soluble than sodium chloride in water.
Yes, sodium iodide (NaI) is highly soluble in water. It dissolves readily to form a clear solution.
The filtrate of lead nitrate and sodium iodide would contain soluble sodium nitrate and insoluble lead iodide. Lead iodide is a yellow solid that precipitates out of the solution, while sodium nitrate remains in the filtrate as it is soluble in water.
Benzene is nonpolar, so its molecules do not have any strong attraction to sodium chloride, which is ionic.
Sodium iodide is soluble in water.
Yes. Simple alkali metal salts tend to be soluble with extremely few exceptions; most halides are likewise soluble. An alkali metal halide, such as sodium iodide, should be expected to be extremely soluble in water.
Sodium iodide is highly soluble in water, with a solubility of approximately 184 grams per 100 mL of water at room temperature. This high solubility is due to the strong ionic interactions between the sodium cation and the iodide anion with water molecules.
No, NaCL is polar, benzen is non-polar.
No, sodium sulfate (Na2SO4) is not soluble in benzene because it is a polar compound and benzene is a nonpolar solvent. Therefore, they will not form a homogeneous solution.
This is a precipitation reaction. Halides of silver are insoluble in water (except silver fluoride) whereas all nitrates are soluble in water. Sodium salts are soluble. Thus, silver iodide is the precipitate. Formula: AgNO3(aq) + NaI(aq) -> AgI(s) + NaNO3(aq)
The ionic compound of sodium iodide is NaI. It is composed of sodium (Na+) ions and iodide (I-) ions held together by ionic bonds.