The solubility of sodium nitrate in benzene is likely extremely low. I know that its solubility in dry acetonitrile (<40 ug/mL H2O) is less than 1 mg/mL. So I would guess it would be even worse in a non-polar solvent like benzene.
Benzene is a non polar solvent. Sodium iodide is an ionic salt. So, this salt is unsoluble in benzene.
Sodium iodide is very soluble solubility product of NaI2 is 184
Sodium iodide
Hexane is non polar compound and benzene also non polar compound so non polar comp's soluble in non polar reagents. But sodium chloride is ionic so does nt dissolve benzene in it
Nothing happens, all possible salts are very soluble: Potassium and sodium salts are always soluble!
Sodium iodide.
Sodium chloride is not soluble in benzene.
It is false; sodium iodide is more soluble than sodium chloride in water.
Yes, it is
Sodium iodide is very soluble solubility product of NaI2 is 184
Benzene is nonpolar, so its molecules do not have any strong attraction to sodium chloride, which is ionic.
Sodium iodide is ionic and formaldehyde is polar. Water, being a polar molecule will readily dissolve both. Benzene is nonpolar so it will not readily dissolve polar or ionic substances.
Sodium iodide is soluble in water.
Yes. Simple alkali metal salts tend to be soluble with extremely few exceptions; most halides are likewise soluble. An alkali metal halide, such as sodium iodide, should be expected to be extremely soluble in water.
No, NaCL is polar, benzen is non-polar.
The name of the compound represented by the formula NaI is sodium iodide.
Yes, three salts of group 1 elements (Lithium, Sodium Potassium and salts) are soluble in water.
It ionises in solution, it can be stabilised in a sense by HI and NaOH temporary formation