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C6H8 + 8O2 ===> 6CO2 + 4H2O ... balanced equation
moles hexane = 54.3 g x 1 mol/80 g = 0.679 moles
moles O2 = 78.5 g x 1 mol/32 g = 2.45 moles
Limiting reactant is Oxygen (O2) since need 8 x as much as C6H8
Theoretical yield of CO2 = 2.45 mole O2 x 6 mole CO2/8mole O2 = 1.84 moles CO2
1.84 moles CO2 x 44 g/mol = 80.9 g (answer to 3 sig figs)

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Q: Liquid hexane reacts with gaseous oxygen gas to produce carbon dioxide and gaseous water. What is the theoretical yield of carbon dioxide formed by the reaction of 54.3g of hexane and 78.5g of oxygen?
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