The reaction of sulfur and oxygen to produce sulfur dioxide is called combination or synthesis.
This is an exothermic reaction.
It is a synthesis reaction.
When the combustion is complete, the balanced equation is: C7H16 + 11 O2 -> 7 CO2 + 8 H2O.
2C5H12 +11 O2 ------------->10 CO +12 H2OHydrocarbon combustion produces water(H2O) and carbon dioxide(CO2)C5H12 + 8O2 __ 5CO2 + 6H2O
The correct answer is: C5H12 + 8O2 5CO2 + 6H2O.
Firdt oh all qrite down the balanced reaction equation. S(s) + O2(g) = SO2(g) Note all the molar Ratios are 1:1 ::1 Next calculate the moles of sulphur moles(S) = 0.5 / 32 = 0.015625 moles. (Equivalent to '1' ratio). Moles(O2) = 0.015625 ( Equivalenbt to '1' ratio). Hence mass of oxygen is mass(g) = moles X Mr Me( Relative Molecular Mass) of oxygen (O2) is 16 X 2 = 32 Hence mass = 0.015625 X 32 = 0.5 g (mass of oxygen(O2) required).
It is a synthesis reaction.
It's an Oxidation-reduction
S8 + 8o2 --> 8so2
When the combustion is complete, the balanced equation is: C7H16 + 11 O2 -> 7 CO2 + 8 H2O.
Burning pentane, C5H12, is a combustion reaction in which pentane and oxygen will react to form carbon dioxide and water. The chemical equation is C5H12 + 8O2 --> 5CO2 + 6H2O
The number of atoms of each element must be the same on both sides of the equation. Therefore, the reaction is as follows: S8 + 8O2 ---> 8SO2 Keep in mind that the subscripts of the products and reactants cannot be changed.
I get 2C6H14+19O2------->12CO2+14H2O
C5h12 + 8o2 --> 5co2 + 6h2o
2C5H12 +11 O2 ------------->10 CO +12 H2OHydrocarbon combustion produces water(H2O) and carbon dioxide(CO2)C5H12 + 8O2 __ 5CO2 + 6H2O
The correct answer is: C5H12 + 8O2 5CO2 + 6H2O.
C5H12 + 8 O2 --> 5 CO2 + 6 H2O (1 mol O2)(6 mol H2O/8 mol O2) = 0.75 mol H2O
Firdt oh all qrite down the balanced reaction equation. S(s) + O2(g) = SO2(g) Note all the molar Ratios are 1:1 ::1 Next calculate the moles of sulphur moles(S) = 0.5 / 32 = 0.015625 moles. (Equivalent to '1' ratio). Moles(O2) = 0.015625 ( Equivalenbt to '1' ratio). Hence mass of oxygen is mass(g) = moles X Mr Me( Relative Molecular Mass) of oxygen (O2) is 16 X 2 = 32 Hence mass = 0.015625 X 32 = 0.5 g (mass of oxygen(O2) required).