NO3- is a spectator ion.
Potassium (K+) is a spectator ion in this reaction. It appears both on the reactant side (K+ and NO3-) and product side (K+ and NO3-), but does not participate in the actual reaction forming the solid silver bromide (AgBr).
The spectator ion is NO3- from Ba(NO3)2, as it remains unchanged throughout the reaction and does not participate in forming the precipitate of Ba3(PO4)2.
The molecular equation is 3Ba(NO3)2(aq) + 2(NH4)3PO4(aq) ==> Ba3(PO4)2(s) + 6NH4NO3(aq)The spectator ions are NH4^+ and NO3^-
The ion name for NO3 is nitrate.
The formula for the nitrate ion is NO3-.
Potassium (K+) is a spectator ion in this reaction. It appears both on the reactant side (K+ and NO3-) and product side (K+ and NO3-), but does not participate in the actual reaction forming the solid silver bromide (AgBr).
The spectator ion is NO3- from Ba(NO3)2, as it remains unchanged throughout the reaction and does not participate in forming the precipitate of Ba3(PO4)2.
The molecular equation is 3Ba(NO3)2(aq) + 2(NH4)3PO4(aq) ==> Ba3(PO4)2(s) + 6NH4NO3(aq)The spectator ions are NH4^+ and NO3^-
The ion name for NO3 is nitrate.
The spectator ions in this reaction are Mg2+ and NO3- because they appear on both sides of the chemical equation and do not participate in the actual chemical reaction. They are simply there as part of the compounds but do not change during the reaction.
The formula for the nitrate ion is NO3-.
NO3- is the term.
The spectator ions in this reaction are Na+ and NO3-. They remain unchanged on both sides of the equation and do not participate in the formation of the precipitate AgI.
Nitraite = NO3 One Nitrogen atom (N) Three Oxygen atoms (O3)
The spectator ions are Ag+ and (NO3)-.
I believe that would be Barium nitrate or Ba(NO3)2
spectator ion